the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
Answer: i'm pretty sure todd's score would be 19
39=2x-1
Answer:
k = 37
Step-by-step explanation:
k = 13t - 2 Since the input, t, is 3, substitute it.
k = 13(3) -2 Multiply
k = 39 - 2 Subtract
k = 37
If this answer is correct, please make me Brainliest!
79.57 times 12% = 70.02
70.02 times 7.75% = 5.43
70.02 plus 5.43 = 75.43
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is 
Step-by-step explanation:
From the diagram we can obtain the the height of T as follows
