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Elis [28]
3 years ago
12

HELP ME PLEASE!!!

Physics
2 answers:
Veronika [31]3 years ago
8 0

Answer:

its c edge2020

Explanation:

Ksenya-84 [330]3 years ago
5 0
(15.9 - 15.6) / 15.9 × 100% (because the actual weight is 15.9)
1.8868% = 1.89%
Answer: D

Hope it helped!
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A snow ball is thrown upward at a speed of 27 m/s. How high is the snow ball 3.5 seconds later? Also, how fast is it moving at t
JulijaS [17]

Answer:

Dy = 111.66 [m]

t  = 3.5 [s]

Explanation:

To solve this problem we must use the equations of kinematics.

v_{f} = v_{o} - (g*t)\\

where:

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Vo = initial velocity = 27 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time = 3.5 [s]

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Vf = 27 - (9,81*3,5)

Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)

To find how high the snowball was we must use the following equation:

Dy=v_{o} *t+\frac{1}{2}*g*t

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Dy = 111.66 [m]

5 0
3 years ago
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