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kobusy [5.1K]
3 years ago
14

Plz I need help !!!!!!!

Physics
1 answer:
Olenka [21]3 years ago
8 0
The Density of this Rectangular Prism would be 7.5, since the Volume of the Rectangular Prism can be determined by using the formula: length times width times height.

5*2*4, or 2*4*5, or 5*4*2= 40, because 5*2= 10, and 10*4= 40.
The Problem hereby, states that the mass of the Rectangular Prism is 300 grams, right?

Since the Formula for calculating the Density of an Object is Mass divided by Volume, 300 divided by 40 gives you 7.5, and we wouldn't make the answer 7.5 cubed, or 7.5 squared, or 7.5 grams cubed, or 7.5 grams squared, since squared would be for finding only the Area for 2-D Shapes, and cubed would be for finding only the Volume for 3-D Shapes, but in this case that we had here, We were finding Density, which includes Mass AND Volume, not just Volume.
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While a roofer is working on a roof that slants at 39.0 degrees above the horizontal, he accidentally nudges his 88.0 N toolbox,
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Answer:

V= 6.974 m/s

Explanation:

Component( box) weight acting parallel and down roof 88(sin39.0°)=55.4 N

Force of kinetic friction acting parallel and up roof = 18.0 N

Fnet force acting on tool box acting parallel and down roof

Fnet= 55.4 - 18.0

Fnet=37.4 N

acceleration of tool box down roof

a = 37.4(9.81)/88.0

a= 4.169 m/s²

d = 4.90 m

t = √2d/a

t= √2(4.90)/4.169

t= 1.662 s

V = at

V= 4.169(1.662)

V= 6.974 m/s

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Who won the Battle of Barren Hill?
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3 years ago
A 2000-kg sailboat experiences an eastward force of 2000 N by the ocean tide and a wind force against its sails with magnitude o
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Answer:

The force exerted by the ocean tide is directed to the right (east).

The force exerted by the wind is directed to the northwest (45° N of W).

We should separate the x- and y- components of the wind force, and evaluate each component separately.

F_x = 6000\cos(\pi/4)(-\^{x})\\F_y = 6000\sin(\pi/4)(+\^{y})

We denote the direction to the right as the positive direction, so the x-component of the wind force is in the negative direction.

The resultant force is as follows:

F_R = [2000 - 4242.64](\^{x}) + [4242.64](\^{y})\\F_R = -2242.64\^{x} + 4242.64\^{y}

The resultant acceleration can be found by Newton's Second Law:

F = ma\\\\a_R = F_R/m = -1.12\^{x} + 2.12\^{y}

The magnitude of the resultant acceleration is

|a_R| = \sqrt{(1.12)^2 + (2.12)^2} = 2.4 ~m/s^2

7 0
3 years ago
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