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Naily [24]
3 years ago
8

A snow ball is thrown upward at a speed of 27 m/s. How high is the snow ball 3.5 seconds later? Also, how fast is it moving at t

hat time?
Physics
1 answer:
JulijaS [17]3 years ago
5 0

Answer:

Dy = 111.66 [m]

t  = 3.5 [s]

Explanation:

To solve this problem we must use the equations of kinematics.

v_{f} = v_{o} - (g*t)\\

where:

Vf = final velocity [m/s]

Vo = initial velocity = 27 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time = 3.5 [s]

Note: The negative sign of the equation means that the gravity acceleration goes in opposite direction

Vf = 27 - (9,81*3,5)

Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)

To find how high the snowball was we must use the following equation:

Dy=v_{o} *t+\frac{1}{2}*g*t

Dy = (27*3.5) + (0.5*9.81*3.5)

Dy = 94.5 + (17.16)

Dy = 111.66 [m]

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Cerrena [4.2K]

Answer:

D) 11 m/s

Explanation:

We have to calculate the velocity of the hot dog with respect to the observer still outside the train. This velocity will be given by:

v=v_t + v_m + v_h

where

v_t=+10 m/s is the velocity of the train (towards right)

v_m=+2 m/s is the velocity of the man (towards right)

v_h=-1 m/s is the velocity of the hot-dog (towards left, so we put a negative sign)

By replacing the numbers into the equation, we find

v=+10 m/s+2 m/s-1 m/s=+11 m/s

and the positive sign means the velocity is toward right.

5 0
4 years ago
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GuDViN [60]

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If the diver is just standing there, then the reaction force provided by the cliff
against his feet must be exactly equal to his weight.  If the vertical forces acting
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His weight is  (mass) x (gravity) =

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6 0
4 years ago
When a raw egg gets heated into an edible egg is this considered a physical or chemical change?
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Answer:

it is a physical change

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Coherent light with wavelength 603 nm passes through two very narrow slits, and the interference pattern is observed on a screen
valina [46]

Answer:

λ  = 4.023 10⁻⁷ m

Explanation:

The double-slit interference phenomenon is described by

          d sin θ = (m + ½) λ          destructive interference

          d sin θ = m λ                  constructive interference

we can use trigonometry

         tan θ = y / L

how these experiments occur for small angles

         tan θ = sin θ/cos θ = sin θ

         sin θ = y / L

we substitute

        d y / L = (m + ½) λ        destructive interference

        d y / L = m λ                 constructive interference

with the expression for constructive interference we look for the separation of the slits

        d = m λ L / y

        d = 1 603 10⁻⁹ 3 /4.84 10⁻³

        d = 3.738 10⁻⁴ m

Now let's analyze the case where the distance for constructive and destructive interference occurs at the same point y = 4.84 mm = 4.84 10⁻³m

          d y / L = (m + ½)  λ

          λ = \frac{ d \ y}{L\  (m+ 1/2) }

the first strip is for m = 1  

let's calculate

         λ  = \frac{3.738 \ 10^{-4} 4.84 \ 10^{-3} }{ 3 \  ( 1 + 0.5) }

         λ  = 4.023 10⁻⁷ m

       

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3 years ago
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