Answer:
Explanation:
If we let our reference frame travel at 30 m/s with the constant speed car, The accelerating car increases its velocity by 10 m/s in 3 seconds.
The average velocity of the accelerating car is (0 + 10) / 2 = 5 m/s
It will advance its position 5 m/s(3 s) = 15 m in the accelerating period.
It takes 5 + 3 = 8 m for the two cars to become side by side.
It would take another 5 + 3 = 8 m for the accelerating car to leave a gap of 3 m between.
The car requires 8 + 8 = 16 m to pass the other safely but the acceleration period only gets him to 15 m.
So despite your saying this is not a YES / NO question, the answer is NO the acceleration is too low or not long enough to meet the required clearances.
Input needed is 10000 J/s / 0.30 = 333333 = J/s
three hours requires 333333(3)(3600) = 360 MJ of energy
360 MJ / 34 MJ/liter = 10.6 liters.
To calculate speed, you need to know the total distance covered
and the time it took to cover the distance.
To calculate velocity, you need the starting location, the ending location,
and the time it took to go from start to finish.
Answer:
The neutron loses all of its kinetic energy to nucleus.
Explanation:
Given:
Mass of neutron is 'm' and mass of nucleus is 'm'.
The type of collision is elastic collision.
In elastic collision, there is no loss in kinetic energy of the system. So, total kinetic energy is conserved. Also, the total momentum of the system is conserved.
Here, the nucleus is still. So, its initial kinetic energy is 0. So, the total initial kinetic energy will be equal to kinetic energy of the neutron only.
Now, final kinetic energy of the system will be equal to the initial kinetic energy.
Now, as the nucleus was at rest initially, so the final kinetic energy of the nucleus will be equal to the initial kinetic energy of the neutron.
Thus, all the kinetic energy of the neutron will be transferred to the nucleus and the neutron will come to rest after collision.
Therefore, the neutron loses all of its kinetic energy to nucleus.
Answer:
Sliding friction is the force that sliding objects experience
Explanation:
