Answer:
The magnitude of the acceleration of the 19 kg block is 1.414 m/s²
Explanation:
From Newton's second law of motion;
where;
m is the mass of the objects involved, kg
a is the acceleration of the object, m/s²
different forces on the block and string
⇒force due to 15 kg block
=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396
= 138.12 N
⇒Tensional Force on 19 kg mass:
T = mg = 19×9.8 = 186.2 N
186.2 - 138.12 = a(15+19)
48.08 = a(34)
a = 48.08/34
a = 1.414 m/s²
Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²
Answer:
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Explanation:
the ಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠಠᴥಠ
Answer:
A. 58.8m/s
Explanation:
The acceleration due to gravity is 9.8 m/s², so the velocity after 6 seconds is ...
v = at
v = (9.8 m/s²)(6 s) = 58.8 m/s
Answer:
Spring constant, k = 1.16 N/m
Explanation:
It is given that,
Mass of the air track, m = 0.2 kg
Time, t = 2.6 s
Let T is the time period of the spring. The expression for the time and spring constant is given by :
k = 1.16 N/m
So, the spring’s force constant is 1.16 N/m. Hence, this is the required solution.
Measures angular displacement per unit time.
