4 x n^2
four times a number that is squared
nswer:
209.8
Step-by-step explanation:
the bottom is = 11 * 5
two of the sides are 11 * 9.3 / 2 because they are triangles, and then times 2 because there are two of them
the other two sides are 10.5 * 5 / 2 , and the * 2 because there are two of them again.
(11 * 5) + (11 * 9.3 * 2 / 2) + (10.5 * 5 * 2 / 2) =209.8
Total students - Nepali only - English only = bilingual
60-30-15= 15 students can speak both languages.
F(x)=4x+1
g(x)=x^2-5
(f . g)(x)=?
(f . g)(x) = f(x) . g(x) = (4x+1).(x^2-5)=(4x).(x^2)+(4x).(-5)+(1).(x^2)+(1).(-5)
(f . g)(x) = 4x^(1+2)-20x+x^2-5
(f . g)(x)=4x^3+x^2-20x-5
Answer: Option A. 4x^3+x^2-20x-5
To find this you would just subtract 28 - 3 = 5. So now you subtract 28 - 5 = 23.
- 23-5= 18 etc. so on and so forth. Your numbers would be 28, 23, 18, 13, 8, 3.