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Svetlanka [38]
3 years ago
8

A circular table has a diameter of 48 inches. A carpenter is remaking it into a square table. To the nearest tenth of an inch, w

hat is the greatest possible side length of the square table?
Mathematics
1 answer:
ad-work [718]3 years ago
3 0
If the diameter of the circle is 48 the maximum diagonal of the square is 48.

The diagonal of the square is:

d=√x^2+x^2

d=√2x^2 so

48=x√2

x=48/√2 in

x≈33.9 in
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I'm pretty sure this is easy for some of you but not me!
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The possible outcomes are H1, H2, T1, and T2

Step-by-step explanation:

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A man 50 years old has 8 sons born of equal intervals. The sum of the ages of the father and sons is 186. What is the age of the
Rudiy27
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4 years ago
Square root of 5 + square root of 3 the whole divided by sqaure root of 5 - square root of 3
xxMikexx [17]

Answer:

The answer is 4 + √15 .

Step-by-step explanation:

You have to get rid of surds in the denorminator by multiplying it with the opposite sign :

\frac{ \sqrt{5}  +  \sqrt{3} }{ \sqrt{5}  -  \sqrt{3} }

=  \frac{ \sqrt{5} +  \sqrt{3}  }{ \sqrt{5}  -  \sqrt{3} }  \times  \frac{ \sqrt{5}  +  \sqrt{3} }{ \sqrt{5}  +  \sqrt{3} }

=  \frac{ {( \sqrt{5} +  \sqrt{3} ) }^{2} }{( \sqrt{5} -  \sqrt{3} )( \sqrt{5}  +  \sqrt{3})  }

=   \frac{ {( \sqrt{5} )}^{2}  + 2( \sqrt{5} )( \sqrt{3}) +  {( \sqrt{3}) }^{2}  }{ {( \sqrt{5}) }^{2} -  { (\sqrt{3} )}^{2}  }

=  \frac{5 + 2 \sqrt{15} + 3 }{5 - 3}

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3 0
3 years ago
Does anybody know the answer to these questions?
san4es73 [151]

Answer:

  1. 625,000 J

  2. 100 J

  4. 5 kg

  5. √5 ≈ 2.236 m/s

Step-by-step explanation:

You should be aware that the SI derived units of Joules are equivalent to kg·m²/s².

To reduce confusion between <em>m</em> for mass and m for meters, we'll use an <em>italic m</em> for mass.

In each case, the "find" variable is what's left after we put the numbers into the formula. It is what the question is asking for. The "given" values are the ones in the problem statement and are the values we put into the formula. The formula is the same in every case.

__

1. KE = (1/2)<em>m</em>v² = (1/2)(2000 kg)(25 m/s)² = 625,000 kg·m²/s² = 625,000 J

__

2. KE = (1/2)<em>m</em>v² = (1/2)(0.5 kg)(20 m/s)² = 100 kg·m²/s² = 100 J

__

4. KE = (1/2)<em>m</em>v²

  250 J = (1/2)<em>m</em>(10 m/s)² = 50 m²/s²

  (250 kg·m²/s²)/(50 m²/s²) = <em>m</em> = 5 kg

__

5. KE = (1/2)<em>m</em>v²

  2000 kg·m²/s² = (1/2)(800 kg)v²

  (2000 kg·m²/s²)/(400 kg) = v² = 5 m²/s²

  v = √5 m/s ≈ 2.236 m/s

7 0
3 years ago
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