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2 years ago

All of number 3 plz and thank u!

Mathematics

1 answer:

Zielflug [23.3K]2 years ago

7 0

Hey what class is this for so I can help

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Rewrite in a form that does not use exponents

emmainna [20.7K]

Answer:

$\boxed{18}$

Step-by-step explanation:

One of the rules of logarithms is ...

log(a^b) = b·log(a)

So ...

$6\log_5{x^3}=6(3\log_5{x})=\bf{18}\log_5{x}$

4 0

3 years ago

What is the value of y in the equation 4(5y –8 –2) = 185 –15?

Rina8888 [55]

In an equation the Left hand side must equal the right hand side 4(5y-8-2)=185-15 20y-32-8=170 20y=170+32+8 20y=210 Therefore y=10,5 When you substitute the 10,5 and solve it on the left and side it's equal to 170 which is the answer on the right hand side

8 0

2 years ago

WHAT IS THE VALUE OF X?

Tanzania [10]

It is a similar triangle so the side length of the smaller triangle (x and x-2) are in the same ratio as the bigger triangle (2x+5 and 2x-1). As the ratio is the same, you can equate them and solve for x.

7 0

2 years ago

Help pls <br> Show workings

vitfil [10]

- the type of pair is vertical angle.

- to find x:

-- vertical angles are equal.

4x + 10 = 5x - 1

10 = x - 1

x = 11

6 0

3 years ago

How do you solve 9| x+8 | + 10 < 55 & how is it graphed

mafiozo [28]

Hello!

First, let's write the problem.
$9\left|x+8\right|+10\ \textless \ 55|x+8|+10\ \textless \ 55$
Subtract 10 from both sides.
$9\left|x+8\right|+10-10\ \textless \ 55-10$
$9\left|x+8\right|\ \textless \ 45$
Divide both sides by 9.
$\frac{9\left|x+8\right|}{9}\ \textless \ \frac{45}{9}$
$\left|x+8\right|\ \textless \ 5$
When we got absolute value, we are going to get two results.
$x+8\ \textless \ 5$
and
$x+8\ \textgreater \ -5$

Let's solve the first one,
$x+8\ \textless \ 5x+8\ \textless \ 5$
Subtract 8 from both sides.
$x+8-8\ \textless \ 5-8$
$x\ \textless \ -3x\ \textless \ -3$

Let's solve the second one.
$x+8\ \textgreater \ -5$
Subtract 8 from both sides.
$x+8-8\ \textgreater \ -5-8$
$x\ \textgreater \ -13x\ \textgreater \ -13$

Let's combine the ranges.
$-13\ \textless \ x\ \textless \ -3$

The attachment shows how would you graph it.
You can feel free to let me know if you have any questions regarding this.
Thanks!

- TetraFish

3 0

2 years ago