Answer:



Explanation:
M = Mass of Uranus
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
r = Radius of Uranus = 25360 km
h = Altitude = 104000 km
= Radius of Miranda = 236 km
m = Mass of Miranda = 
Acceleration due to gravity is given by

The mass of Uranus is 
Acceleration is given by

Miranda's acceleration due to its orbital motion about Uranus is 
On Miranda

Acceleration due to Miranda's gravity at the surface of Miranda is 
No, both the objects will fall towards Uranus. Also, they are not stationary.
thw answer is C. 2
i do not know why! Sorry!
i just took the test and it was right
To determine the maximum height for the projectile, we can use the timeless kinematics equation

and plug in what we know. For

, we know it is zero because at the highest location of flight, there is no vertical velocity. For

, we know it is

since the vertical component is the sine of the velocity. We need to solve for

, so it is left as-is. Since the only acceleration is

, we can substitute -9.81 into it. Solving for the equation yields a solution of 17.55 m for

.
Answer:
ρ = 1469 kg/m³
Explanation:
given,
mass of statue = 0.4 Kg
density of statue = 8 x 10³ kg/m³
tension in the string = 3.2 N
density of the fluid = ?
Volume of the statue

V = 5 x 10⁻⁵ m³
W = ρ g V
W = ρ x 9.8 x 5 x 10⁻⁵
now, tension on the string will be equal to
T = mg - W
3.2 = 0.4 x 9.8 - ρ x 9.8 x 5 x 10⁻⁵
ρ x 9.8 x 5 x 10⁻⁵ = 0.72
ρ = 1469 kg/m³