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KIM [24]
3 years ago
8

What was your favorite thing to learn in physics

Physics
1 answer:
Zepler [3.9K]3 years ago
5 0

Answer:

<h2>Three laws of motion haha.....</h2>
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The planet Uranus has a radius of 25,360 km and a surface acceleration due to gravity of 9.0 m/s^2 at its poles. Its moon Mirand
AlexFokin [52]

Answer:

8.67791\times 10^{25}\ kg

0.34589\ m/s^2

0.07903\ m/s^2

Explanation:

M = Mass of Uranus

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Uranus = 25360 km

h = Altitude = 104000 km

r_m = Radius of Miranda = 236 km

m = Mass of Miranda = 6.6\times 10^{19}\ kg

Acceleration due to gravity is given by

g=\dfrac{GM}{r^2}\\\Rightarrow M=\dfrac{gr^2}{G}\\\Rightarrow M=\dfrac{9\times 25360000^2}{6.67\times 10^{-11}}\\\Rightarrow M=8.67791\times 10^{25}\ kg

The mass of Uranus is 8.67791\times 10^{25}\ kg

Acceleration is given by

a_m=\dfrac{GM}{(r+h)^2}\\\Rightarrow a_m=\dfrac{6.67\times 10^{-11}\times 8.67791\times 10^{25}}{(25360000+104000000)^2}\\\Rightarrow a_m=0.34589\ m/s^2

Miranda's acceleration due to its orbital motion about Uranus is 0.34589\ m/s^2

On Miranda

g_m=\dfrac{Gm}{r_m^2}\\\Rightarrow g_m=\dfrac{6.67\times 10^{-11}\times 6.6\times 10^{19}}{236000^2}\\\Rightarrow g_m=0.07903\ m/s^2

Acceleration due to Miranda's gravity at the surface of Miranda is 0.07903\ m/s^2

No, both the objects will fall towards Uranus. Also, they are not stationary.

6 0
3 years ago
If an astronomical object's parallax is one-half arcsecond, how many parsecs is it from Earth?
Mariulka [41]

thw answer is C. 2

i do not know why! Sorry!

i just took the test and it was right

6 0
3 years ago
Read 2 more answers
a projectile leaves the ground with a velocity of 35 meters per second at an angle 32° what is the maximum height
Nina [5.8K]
To determine the maximum height for the projectile, we can use the timeless kinematics equation V _{f} ^{2} -V_{i}^{2}=2a \Delta y and plug in what we know. For V _{f} ^{2}, we know it is zero because at the highest location of flight, there is no vertical velocity. For V _{i} ^{2}, we know it is (35sin(32))^{2} since the vertical component is the sine of the velocity. We need to solve for y, so it is left as-is. Since the only acceleration is g, we can substitute -9.81 into it. Solving for the equation yields a solution of 17.55 m for \Delta y.
6 0
4 years ago
Lava that cools so quickly that ions do not have time to arrange into crystals will form igneous rocks with a _____.
tamaranim1 [39]
The answer is glassy texture
8 0
3 years ago
A brass statue with a mass of 0.40 kg and a density of 8.00×103kg/m3 is suspended from a string. When the statue is completely s
Mars2501 [29]

Answer:

ρ = 1469  kg/m³

Explanation:

given,

mass of statue = 0.4 Kg

density of statue = 8 x 10³ kg/m³

tension in the string = 3.2 N

density of the fluid = ?

Volume of the statue

V = \dfrac{0.4}{8\times 10^3}

V = 5 x 10⁻⁵ m³

W = ρ g V

W = ρ x 9.8 x 5 x 10⁻⁵

now, tension on the string will be equal to

T = mg - W

3.2 = 0.4 x 9.8 - ρ x 9.8 x 5 x 10⁻⁵

ρ x 9.8 x 5 x 10⁻⁵ = 0.72

ρ = 1469  kg/m³

8 0
3 years ago
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