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topjm [15]
3 years ago
8

What does the variable a meand in physics

Physics
1 answer:
earnstyle [38]3 years ago
7 0
Can you tell me which variable do you looking for.
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Running with an initial velocity of +11m/s, a horse has an average acceleration of -1.81m/s 2 . How long does it take for the ho
Ronch [10]

Answer:

2.49 seconds

Explanation:

From the question,

a = (v-u)/t............................ Equation 1

Where a = acceleration, v = final velocity, u = initial velocity, t = time

Make t the subject of the equation

t = (v-u)/a.......................... Equation 2

Given: v = 6.5 m/s, u = 11 m/s, a = -1.81 m/s²

Substitute these values into equation 2

t = (6.5-11)/(-1.81)

t = -4.5/-1.81

t = 2.49 s

6 0
3 years ago
Why are fossil fuels like coal, oil, and natural gas<br> called nonrenewable resources?
Elena L [17]
After they are all used up they can’t be renewed or used anymore.
3 0
4 years ago
Two children hang by their hands from the same tree branch. the branch is straight, and grows out from the tree trunk at an angl
Ratling [72]

The net torque exerted by the children on the branch of the tree is 1382 N-m.

The torque exert by the kids is calculated as

T= 45.6*9.8*1.28*cos27.5°+36*9.8*(2.25-1.28)cos27.5°

T=1382 N-m

Hence, The net torque exerted by the children on the branch of the tree is 1382 N-m.

7 0
4 years ago
A sound wave has frequency of 430 Hz in air . Which of these is closet to the wavelength of this sound? ( The speed of sound in
Darya [45]
I think it would be E. The higher the object the less wavelength is possible.
5 0
3 years ago
An open pipe, 0.29 m long, vibrates in the second overtone with a frequency of 1,227 Hz. In this situation, the fundamental freq
Andru [333]

Answer:

f = 409 Hz

Explanation:

We have,

Length of the open organ pipe, l = 0.29 m

Frequency of vibration of second overtone, f_2 = 1227 Hz

It is required to find the fundamental frequency of the pipe. For the open organ pipe, the frequency of second overtone is given by :

f_2=\dfrac{3v}{2l}

v is speed of sound

Let f is the fundamental frequency. It is given by :

f=\dfrac{v}{2l}

The relation between f and f₂ can be written as :

f_2=3f\\\\f=\dfrac{f_2}{3}\\\\f=\dfrac{1227}{3}\\\\f=409\ Hz

So, the fundamental frequency of the pipe is 409 Hz.              

6 0
3 years ago
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