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Pavlova-9 [17]
3 years ago
8

What is the velocity of a fly with a mass of approximately 6.85 times 10 to the negative 6 slugs if it has a kinetic energy of 5

.95 J?
Physics
1 answer:
vodka [1.7K]3 years ago
4 0

Velocity of the fly: 1318 m/s

Explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion. It can be calculated as

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

For the fly in this problem, we have

m=6.85\cdot 10^{-6} kg is the mass

K = 5.95 J is the kinetic energy

Solving for v, we find its velocity:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(5.95)}{(6.85\cdot 10^{-6})}}=1318 m/s

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

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A 0.030 kg lead bullet hits a steel plate, both initially at 20?C. The bullet melts and splatters on impact. Assume that 80% of
Dmitry_Shevchenko [17]

Answer:

(a). The required is 1871.2 J.

(b). The speed the lead bullet is 395 m/s.

(c). The 20% of energy must have gone into collision between steel plate and bullet.

Explanation:

Given that,

Mass of bullet = 0.030 kg

Temperature = 20°C

(a). We need to heat required to increase the temperature of the lead bullet and melt it

Using formula of heat

Q=mS\Delta T+mL

Where, m = mass of lead bullet

S = specific heat

L = latent heat

T = Temperature

Put the value into the formula

Q=0.030\times130\times(327.5-20)+0.030\times22400

Q=1871.2\ J

The required is 1871.2 J.

(b). Assume that 80% of the bullet’s kinetic energy goes into increasing its temperature and then melting it

We need to calculate the energy

Q=\dfrac{1871.2}{0.8}

Q=2339 J

We need to calculate the speed the lead bullet

Using formula of speed

K.E=Q

\dfrac{1}{2}mv^2=2339

v^2=\dfrac{2339\times2}{0.030}

v=\sqrt{\dfrac{2339\times2}{0.030}}

v=394.8 = 395\ m/s

The speed the lead bullet is 395 m/s.

(c). The 20% of energy must have gone into collision between steel plate and bullet.

Hence, This is the required solution.

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3 years ago
Enunciado del ejercicio n° 1
hoa [83]

Answer:

34

Explanation:

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