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sammy [17]
4 years ago
13

5. If the cars are traveling at a constant speed, do they have a balanced force or an unbalanced force acting upon them?

Physics
2 answers:
Ostrovityanka [42]4 years ago
5 0
The answer would be balanced force because if the cars are at a constant speed and neither of them are changing by going faster or slowing down, than its equal.
Eva8 [605]4 years ago
5 0
Balanced forces is the answer
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Give an example of an atom that will give up its outermost electron easily. Explain why you chose this atom.
BARSIC [14]

Answer:

Cesium (Cs)

very low electronegativity

there are a bunch of cool videos online about Cesium reacting with water

most are faked but the general idea is a cool one as Cesium very quickly and easily gives up it's one and only outermost (or valence) electron

Explanation:

4 0
3 years ago
Badri makes the table below to review the factors that affect the electric force between objects. Which change will correct the
kirill115 [55]

Answer:

Changing "Mass" to "Amount of electric charge"

4 0
4 years ago
Read 2 more answers
A standard steel pipe (D = 3.81 in.; d = 3.24 in.) supports a concentrated load of P = 930 lb. The span length of the cantilever
Maurinko [17]

Answer:

a) τmax = 586.78 P.S.I.

b) σmax = 15942.23 P.S.I

Explanation:

D = 3.81 in

d = 3.24 in

P = 930 lb

L = 3.7 ft = 44.4 in

a) The maximum horizontal shear stress can be obtained as follows

τ = V*Q / (t*I)

where

V = P = 930 lb

Q = (2/3)*(R³- r³) = (1/12)*(D³- d³) = (1/12)*((3.81 in)³- (3.24 in)³)

⇒ Q = 1.7745 in³

t = D - d = 3.81 in - 3.24 in = 0.57 in

I = (π/64)*(D⁴-d⁴) = (π/64)*((3.81 in)⁴- (3.24 in)⁴) = 4.9341 in⁴

then

τ = (930 lb)*(1.7745 in³) / (0.57 in*4.9341 in⁴)

⇒ τmax = 586.78 P.S.I.

b) We can apply the following equation in order to get the maximum tension bending stress in the pipe

σmax = Mmax *y / I

where

Mmax = P*L = 930 lb*44.4 in = 41292 lb-in

y = D/2 = 3.81 in /2 = 1.905 in

I = 4.9341 in⁴

then

σmax = (41292 lb-in)*(1.905 in) / (4.9341 in⁴) = 15942.23 P.S.I

6 0
4 years ago
A car with mass 1500 kg moves with constant velocity of 36 m/s. The driver sees a group of cows in front and he immediately step
Crazy boy [7]
From laws of motion:

S = ( \frac{v + u}{2} ) \times t
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s


Substitute the values, hence:
S = ( \frac{0 + 36}{2} ) \times 6
S = (18) \times 6 \\  \\ S = 108m

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
Distance = 52m
6 0
4 years ago
What is an example of Convection?
yKpoI14uk [10]
Boiling water. <span>heat goes from the burner into the pot which heats the water at the bottom. this hot water rises and cooler water moves down to replace it, causing a circular motion.</span>
3 0
3 years ago
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