A generator uses electricity to generate energy

If the earth were twice the distance from the sun that it is now, the gravitational force exerted on it by the sun would be: a)

devlian [24]

Answer:

a) 1/4 what it is now

Explanation:

As we know that force of gravitation between two planets at some distance "r" from each other is given as

$F_g = \frac{Gm_1m_2}{r^2}$

now since we know that if the distance between Earth and Sun is changed

So the force of gravity will be given as

$\frac{F_g'}{F_g} = \frac{r_1^2}{r_2^2}$

now we know that the distance between sun and earth is changed to twice the initial distance between them

so we have

$r_2 = 2r_1$

so new gravitational force between sun and earth is given as

$F_g' = \frac{r_1^2}{(2r_1)^2}F_g$

$F_g' = \frac{1}{4}F_g$

4 0

3 years ago

How does nitrogen from the air get into the bodies of plants and animals?

sladkih [1.3K]

Plants get it from the roots or leaves
animals get it by breathing

8 0

4 years ago

An electric force exists between which pair of objects? Check all that apply.

Blababa [14]

An electric force exists between the following:

-Two negative objects

-Two positive objects

-A negative object and a positive object

4 0

3 years ago

(1 point) A rectangular tank that is 3 feet long, 9 feet wide and 12 feet deep is filled with a heavy liquid that weighs 110 pou

Aloiza [94]

Answer:

Explanation:

Work in pumping water from the tank is given as

W = ∫ y dF. From a to b

Where dF is the differential weight of the thin layer of liquid in the tank, y is the height of the differential layer

a is the lower limit of the height

b is the upper limit of the height.

We know that, .

F = ρVg

Where F is the weight

ρ is the density of water

V is the volume of water in tank

g is the acceleration due to gravity

Then,

dF = ρg ( Ady)

We know that the density and the acceleration due to gravity is constant, also the base area of the tank is constant, only the height that changes.

Then,

ρg = 62.4 lbs/ft³

Area = L×B = 3 × 9 = 27ft²

dF = ρg ( Ady)

dF = 1684.8dy

The height reduces from 12ft to 0ft

Then,

W = ∫ y dF. From a to b

W = ∫ 1684.8y dy From 0 to 12

W = 1684.8y²/2 from 0 to 12

W = 842.4 [y²] from y = 0 to y = 12

W = 842.4 (12²-0²)

W = 121,305.6 lb-ft

3 0

3 years ago

Which of the following are true statements? A. Like charges repel B. Unlike charges repel C. Unlike charges attract or D. Charge

Brums [2.3K]

Answer: The correct answers are (A) and (C).

Explanation:

The expression from electrostatic force is as follows;

$F=\frac{kq_{1}q_{1}}{r^{2} }$

Here, F is the electrostatic force, k is constant, r is the distance between the charges and $q_{1},q_{1}$ are the charges.

The electrostatic force follows inverse square law. It is inversely proportional to the square of the distance between the charges. It is directly proportional to the product of the charges.

Like charges repel each other. There is a force of electrostatic repulsion between the like charges. Unlike charges attract each other. There is a force of electrostatic attraction between unlike charges.

The charges are induced on the neutral object when it is placed nearby the charged object without actually touching it.

Therefore, the true statements from the given options are as follows;

Like charges repel.

Unlike charges attract.

7 0

3 years ago