<span>The surface charge density = q/A
So q = surface charge density x Area
The surface area of a sphere of radius R is 4*Pi*R^2. R = d/2 where d is diameter. This leaves us with 1.3/2 = 0.65. Area = 4 * pie * (0.65)^2 = 5.30998.
So the net charge q = 8.1 * 10^(-6) * 5.30998 = 42.47998 * 10^(-6)
The Total electric flux = Q/e_0 where , 8.854 Ă— 10â’12, e_0 is permitivity of free space.
So Flux = 42.47998 * 10^(-6) / 8.854 * 10(â’12) = 4.833 * 10^(-6 - (-12)) = 4.833 * 10^(6)</span>
It would be completely false to state that a <span>virtual image can sometimes be seen on a screen; it just depends on the situation. A virtual image can never be seen on a screen. The correct option among the two options that are given in the question is the second option. I hope the answer has come to your help.</span>
If you include the effects of falling through air, then you have to know the
shape, size, weight, and surface texture of the objects. You also have to
know the height from which they're dropped, and the temperature, pressure,
and humidity of the air. All these things make a difference in how they fall.
If you ignore the effects of falling through air, like build a giant metal tank
and pump all the air out of it, and ONLY talk about the effects of gravity, then
ALL OBJECTS accelerate at the same rate. If you drop two things from the
same height at the same time, then they both hit the ground at the same time,
traveling at the same speed, no matter what they are. They could be a piece of
tissue and a car !
There are several museums where they have a big glass pipe that you can
see through, and they pump the air out of the pipe and drop a feather and a
bowling ball from the top inside at the same time, and they both reach the
bottom together.
If gravity is the only force on an object, then all objects fall at the same rate.
