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For a Rectangular plate has a voltage of +180V and a 'voltage of -5V. , the second plate has the Electric field mathematically given as
E=21.5*10^3v/m
<h3>What is
the field strength?</h3>
Generally, the equation for the Electric field is mathematically given as
E=v/d
Where
v={180-(-5)}v
v=185v
Therefore
E=185/8.6*10^{-3}
E=21.5*10^3v/m
In conclusion, Electric field
E=21.5*10^3v/m
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Answer:
1.62 atm
Explanation:
We can solve the problem by using the ideal gas equation:
where:
p = ? is the pressure of the gas in the tire
V = 8.5 L is the volume of the tire
n = 0.55 mol is the number of moles of the gas
R = 0.0821 atm L / K mol is the gas constant
T = 305 K is the temperature of the gas
By re-arranging the equation and substituting the numbers in, we find:
Answer:
Inverted (displaced downwards)
Explanation:
The pulse becomes INVERTED upon reflecting off the boundary with the wall. That is, an upward-displaced pulse will reflect off the end and return with a downward displacement. This inversion behavior will always be observed when the end of the medium is fixed, like this wall in this instance. This INVERSION BEHAVIOR can also be observed when the medium is connected to another more heavy or more dense medium. And in this case, when the pulse reaches the end of the medium, a portion of the pulse will reflect off the end and return with an inverted displacement. The heavier medium acts like a fixed end to cause the pulse to be inverted.
Summary: a pulse reaching the end of a medium becomes inverted whenever it either:
i. reflects off a fixed end,
ii. is moving in a less dense medium and reflects off a more dense medium.
49 J is the total kinetic energy. If a bowling ball of mass 7.3 kg and radius 9.6 cm rolls without slipping down a lane at 3.1 m/s. Kinetic energy is the energy an bowling ball has because of its motion.
Given: m = 7.3 Kg ; r = 9.4 cm = 0.094 m ; v = 3.1 m
Now total kinetic energy in this case is given by KE = Kinetic energy due to rotation + Kinetic energy due to translation
i,e KE = 1/2*m*v2 + 1/2*I*ω2 where I is the moment of inertia of the bowling ball about it's center and ω is the angular velocity
Now for pure rotation (without slipping) v = rω
also for the ball (solid sphere) I = 2/5*m*r2
Hence our kinetic energy becomes
KE = 1/2*m*v2 + 1/5*m*v2 = 7/10*m*v2
so KE = 0.7*7.3*(3.1)2 = 49.10 J = 49 J
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