The diagram shows a square ABCD with a point inside it which is 1 unit from D, 2 units from A and 3 units from B. Let angle APD=
theta . (a) Show that theta = (3pi)/4 (b Show that if P is outside the square , then theta = pi/4 () Is the situation possible if P is 3 units from C instead of from B?
1 answer:
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1) Either or
∦
(only two possibilities)
2) Assume (one of two possibilities)
3) (if two parallel lines are cut by a transversal, the corresponding angles are congruent)
4) But is not congruent to
(given)
5) So ∦
(only other possibility)