3 years ago

Suppose that t = x+y/1-xy. Show that when x = 1/a and y = 2a-1/a+2, the value of t does not depend on the value of a.

Mathematics

1 answer:

nevsk [136]3 years ago

7 0

Yo mama got spammed so what does that mean you boy

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Which expression is equivalent to StartRoot 128 x Superscript 8 Baseline y cubed z Superscript 9 Baseline EndRoot? Assume y grea

Nataly [62]

Answer:

Option C.

Step-by-step explanation:

The given expression is

$\sqrt{128x^8y^3z^9}$

It can be written as

$\sqrt{(64\cdot 2)\cdot x^8\cdot y^{2+1}\cdot z^{8+1}}$

$=\sqrt{8^2\cdot 2\cdot (x^4)^2\cdot y^{2}\cdot y\cdot (z^{4})^2\cdot z}$

$=\sqrt{(8x^4yz^4)^2\cdot 2yz}$

$=8x^4yz^4\sqrt{2yz}$

Therefore, the correct option is C.

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3 years ago

Solve the equation. Show work for partial credit.

Natali5045456 [20]

Answer:

x = $\frac{8}{5}$

Step-by-step explanation:

Given

$\frac{5}{x}$ + $\frac{3}{x}$ = 5 ← combine terms on left side

$\frac{8}{x}$ = 5 ( multiply both sides by x )

8 = 5x ( divide both sides by 5 )

$\frac{8}{5}$ = x

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3 years ago

WILL GIVE BRAINLIEST AND 25 POINTS! Evaluate 8 [1/4] A. 0 B. 1 C. 2 D. 3

Leokris [45]

Answer:

Step-by-step explanation:

4×2 (1/4)

The 4 would cancel out to give

2 (1/1) =2

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3 years ago

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Is this relation a function? explain

Anton [14]

Answer:

A function is a relation in which no two ordered pairs have the same first element. A function associates each element in its domain with one and only one element in its range. Solution: a) A = {(1, 2), (2, 3), (3, 4), (4, 5)} is a function because all the first elements are different.

Step-by-step explanation:

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3 years ago

(80 pts) help last question on my test #7 please help !!!

Ierofanga [76]

Step-by-step explanation:

the composite function from K to F :

(F o C) (x) = 9/5 (x - 273.15) + 32 (option D)

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3 years ago