Answer:
4.86moles of barium sulfide are produced
Explanation:
To solve this question we need to convert the mass of barium sulfide (BaS) to moles using the molar mass of BaS:
<em>Molar mass BaS:</em>
<em>1 Ba atom = 137.3g/mol</em>
<em>1 S atom = 32.1g/mol</em>
<em>Molar mass BaS = 137.3 + 32.1 = 169.4g/mol</em>
<em />
<em>Moles in 823g of BaS:</em>
823g * (1mol / 169.4g) =
<h3>4.86moles of barium sulfide are produced</h3>
Answer:
D. It is considered to be a different element than a neutral Sc atom.
There are 2.32 x 10^6 kg sulfuric acid in the rainfall.
Solution:
We can find the volume of the solution by the product of 1.00 in and 1800 miles2:
1800 miles2 * 2.59e+6 sq m / 1 sq mi = 4.662 x 10^9 sq m
1.00 in * 1 m / 39.3701 in = 0.0254 m
Volume = 4.662 x 10^9 m^2 * 0.0254 m
= 1.184 x 10^8 m^3 * 1000 L / 1 m3
= 1.184 x 10^11 Liters
We get the molarity of H2SO4 from the concentration of [H+] given by pH = 3.70:
[H+] = 10^-pH = 10^-3.7 = 0.000200 M
[H2SO4] = 0.000100 M
By multiplying the molarity of sulfuric acid by the volume of the solution, we can get the number of moles of sulfuric acid:
1.184 x 10^11 L * 0.000100 mol/L H2SO4 = 2.36 x 10^7 moles H2SO4
We can now calculate for the mass of sulfuric acid in the rainfall:
mass of H2SO4 = 2.36 x 10^7 moles * 98.079 g/mol
= 2.32 x 10^9 g * 1 kg / 1000 g
= 2.32 x 10^6 kg H2SO4
Answer: They are the same.
Expatiation:
Buoyant force: An upward thrust exerted by any fluid on an object placed in it.
According to Archimedes' principle which states that 'upward thrust exerted by the fluid on an object immersed in a fluid whether partially or fully is equal to the weight of the fluid displaced by the immersed body'.This force acts in the upward direction at the center of mass of the displaced fluid.
Hence, it is correct to say that weight of the water displaced compare to the buoyant force are the same.
