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Julli [10]
4 years ago
9

What is a material that contains three elements joined in a fixed proportion

Chemistry
1 answer:
zepelin [54]4 years ago
5 0

If a material contains three elements joined in a fixed proportion, it is a(an) _____.  

d.) compound

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What volume of 2.0 NaOH is required to neutralize 25.0 ml of 2.70 N H2SO4?<br>​
Viktor [21]

Write the equation for the reaction and balance it. In this case the equation is: 2NaOH + H2SO4 → Na2SO4 + 2H2O

Convert the given amount to moles. Molarity, “M” is moles per liter. The given amount is 25 ml of 1.2 M H2SO4. Since Molarity uses Liters, the volume must be converted from ml to L.

Use the mole ratio in this case 2 moles of NaOH to ! mole of H2SO4

Convert the moles to the required units. In this case the required units are grams. The formula weight in grams er mole.

25 ml H2SO4 * 1L/1000 ml * 1.2 Moles/L * 2 moles NaOH/1 mole H2SO4 * 40 g NaOH/ 1 Mole NaOH

Perform these calculations and you have the answer! Timothy, When doing homework, the answer is NOT the important thing, the METHOD is! These 4 steps, combined with required changes in units will sove ANY stoichiometric problem easily.

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Select the ion.<br><br> a) NO2<br> b)H2SO4<br> c) Al+3 ...?
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I believe the correct answer from the choices listed above is the third option. The ion would be Al+3. It is obvious because among the options, this is the only substance that has a charge. <span>An </span>ion<span> is an atom or a molecule in which the total number of electrons is not equal to the total number of protons, giving the atom or molecule a net positive or negative electrical charge. </span>
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Name the bonds found between amino acids in a polypeptide chain
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Answer:

Explanation:

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How many moles of each element are in one mole of (NH4)2S? (3 points)
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A cat that weighs 55 N sits on the top of a cat tree. It is 2 m above a 110N dog. How does the mass of the animals relate to the
Ivahew [28]

*sorry I can't give a full explanation.*

g = 9.8 m/s²

w = m*g

Weight of cat: 55 N = m*9.8

m = 5.61 kg

Weight of dog: 110 N = m*9.8

m = 11.22 kg

There is gravitational potential energy (GPE) acting on the cat since it's at the very top.

GPE of cat = m*g*h = 5.61*9.8*2 = 109.96 J

GPE of dog = m*g*h = 11.22*9.8*0 = 0 J (it's 0 m height because it's on the floor instead of in the tree)

But, if the dog was also 2 m up in the tree, its GPE would be 219.91 J.

As you can see, it's GRAVITATIONAL potential energy is bigger than the cat because it weighs more. Generally, if you were just trying to find the force which is w = m*g (since weight is a force), you would see that the bigger the mass, the bigger the force, and gravity stays the same.

Hope this helped

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