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mart [117]
3 years ago
9

Please help me its balancing the equation

Chemistry
1 answer:
Vika [28.1K]3 years ago
6 0

Answer:

1, 2, 2, 1

Explanation:

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vovangra [49]
The compound formed is calcium nitrate
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4 years ago
Write the balanced chemical equation for the following reaction. Also, classify the
tekilochka [14]

Answer:

Explanation:

Al2(SO4)3 + 3BaCl2 ====> 2AlCl3 + 3BaSO4

Sorry forgot to say that it is a double replacement. The Ba goes where there Aluminum is and the Aluminum goes where the Barium is.

The internal balance numbers come from the fact that the ions and complex ions have different valance numbers.

3 0
3 years ago
How many grams of c6h12o6 are in 1. 90 x 1022 molecules of c6h12o6? the molar mass of c6h12o6 is 180. 0 g/mol. avogadro's number
d1i1m1o1n [39]

5.6 × 10⁻³ g/mol of C₆H₁₂O₆ are in 1. 90 x 10²² molecules.

The mass per unit amount of a certain chemical entity is known as the molar mass (symbol M, SI unit kgmol1). The chemical entity in question should always be identified in accordance with the mole definition.

The number of atoms present in 1 mole of hydrogen is equal to  6.02 × 10²³ known as Avogadro’s number (NA).

The units of molar mass follow its definition; grams per mole. Mathematically, the defining equation of molar mass is

                         Molar mass = mass/mole = g/mol

180g/mol glucose has = 6.02 × 10²³

x g/mol glucose has = 1.90 × 10 ²²

To find x;

x = \frac{180.0 * 1.90 * 10^2^2}{6.02 * 10^2^3}

x = 5.6 × 10⁻³ g/mol

Therefore,  5.6 × 10⁻³ g/mol of C₆H₁₂O₆ are in 1. 90 x 10²² molecules.

Learn more about molar mass here:

brainly.com/question/837939

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5 0
2 years ago
One hundred fifty joules of heat are removed from a heat reservoir at a temperature of 150 K. What is the entropy change of the
Sidana [21]

Answer:

ΔS surrounding (entropy change of the reservoir) = -1 J/K

Explanation:

Given:

Change in heat (ΔH) = 150 joules

Temperature (T) = 150 K

Find:

ΔS surrounding (entropy change of the reservoir)

Computation:

ΔS surrounding (entropy change of the reservoir) = - ΔH / T

ΔS surrounding (entropy change of the reservoir) = - 150 / 150

ΔS surrounding (entropy change of the reservoir) = -1 J/K

3 0
4 years ago
Find the mass of one mole of FeSO4. Show your addition and multiplication
myrzilka [38]

Answer:

151g/mol

Explanation:

1 Fe =55  1 S =32 4 O =64

7 0
4 years ago
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