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damaskus [11]
3 years ago
8

Does anyone know how to do this? Help please

Mathematics
1 answer:
MArishka [77]3 years ago
3 0

Answer:

ummmmmmmmmmmmmmmmmmmmmm

Step-by-step explanation:

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Find the surface area of the rectangular prism
frutty [35]

Answer:82

Step-by-step explanation:

surface area=pxh + 2xb

p=perimeter of base

h=height

b=area of base

Perimeter of base=7+7+2+2=18

height=3

base area=7x2=14

surface area=18x3+2x14

Surface area=82

7 0
3 years ago
Solve the system of equations. -5x+2y=9. y=7x
il63 [147K]

- 5x + 2y = 9 \\ y = 7x \\  \\  - 5x + 2 \times 7x = 9 \\  - 5x + 14x = 9 \\ 9x = 9 \\ x = 1 \\  \\ y = 7 \times 1 = 7 \\

Answer: (1; 7)

7 0
3 years ago
Find the area of a regular hexagon with side length of 10 and apothem of 8.7 meters <br>HELP PLZZZ​
muminat

Answer:

43.5 meters

Step-by-step explanation:

Area of regular hexagon =

\frac{1}{2}  \times ap

in the problem you have a = 10 meters

and p = apothem = 8.7 meters

so if you apply the formula

you will have

area =( 1/2) × 10 × 8.7

area = 43.5 meters

8 0
3 years ago
Gloria talked on her cell phone for 320 minutes the first mouth , and 489 minutes the third mouth . Her payment package does not
Sliva [168]
Add up minutes

1stmonth+2ndmonth+3rdmonth=320+243+489=1052
how many 200's are there
6 of them (companies want money so they see, ok, you bought like 1 minute, we will charge you for the whole 200 minutes since you got in that zone)

6 times 25=150

cost is $150 (mom is not going to be happy, she spend like 3% of her waking hours takling on the phone)
7 0
3 years ago
(a) Let {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it app
Nataliya [291]

Answer:

0.625

Step-by-step explanation:

Given that {A1, A2} be a partition of a sample space and let B be any event. State and prove the Law of Total Probability as it applies to the partition {A1, A2} and the event B.

Since A1 and A2 are mutually exclusive and exhaustive, we can say

b) P(B) = P(A1B)+P(A2B)

Selecting any one coin is having probability 0.50. and A1, A2 are events that the coins show heads.P(B/A1) = 0.50 \\P(B/A2) = 0.75\\P(A1B) = 0.5(0.5) = 0.25 \\P(A2B) = 0.75(0.5) = 0.375\\P(B) = 0.625

c) Using Bayes theorem

conditional probability that it wasthe biased coin

=\frac{0.375}{0.625} \\=\frac{3}{5}

d) Given that the chosen coin flips tails,the conditional probability that it was the biased coin=\frac{0.25*0.5}{0.25*0.5+0.5*0.5} \\=\frac{1}{3}

7 0
3 years ago
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