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damaskus [11]
3 years ago
8

Does anyone know how to do this? Help please

Mathematics
1 answer:
MArishka [77]3 years ago
3 0

Answer:

ummmmmmmmmmmmmmmmmmmmmm

Step-by-step explanation:

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There are a lot of chickens and sheep in uncle Ben`s Farm, but he sadly forget how many he has now. Only thing he remembers, the
Jobisdone [24]
C+s=48
2c+4s=134  ⇒ c+2s=67

subtracting the equations, we get, s=67-48=19,
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3 years ago
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4/5 to 3/5 as a tenth of a percent
Rudik [331]
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3 years ago
A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)
Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}

5 0
3 years ago
A is set of positive multiples of 5 less than 23
Juli2301 [7.4K]

9514 1404 393

Answer:

  {5, 10, 15, 20}

Step-by-step explanation:

Multiples of 5 are of the form 5n, where n is an integer. The ones of interest will satisfy ...

  0 < 5n < 23

  0 < n < 4.6

That is, the multiples of 5 we want are for values of n that are 1 through 4. The set is ...

  5 × {1, 2, 3, 4} = {5, 10, 15, 20}

3 0
3 years ago
Free brainlest and 100 points <br> have a nice day ;)
labwork [276]
Omgggg thank youuuuu
3 0
3 years ago
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