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liberstina [14]
3 years ago
9

Please write blue splat

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0

Answer:

Blue splat

Step-by-step explanation:

Blue splat

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What is the domain of the relation?
Masja [62]

Answer:

the domain of the relation is C

5 0
2 years ago
there is 29cm if green ribbon. a blue ribbon is 9cm shorter than the green ribbon. how long is the blue ribbon ​
a_sh-v [17]

Answer:20cm

Step-by-step explanation:

If the blue ribbon is 9cm shorter you’re just subtracting 29-9 which is 20cm.

8 0
3 years ago
Use the graph of f '(x) below to find the x values of the relative maximum on the graph of f(x):
Lana71 [14]

Answer:

You have relative maximum at x=1.

Step-by-step explanation:

-Note that f' is continuous and smooth everywhere. f therefore exists everywhere on the domain provided in the graph.

f' is greater than 0 when the curve is above the x-axis.

f' greater than 0 means that f is increasing there.

f' is less than 0 when the curve is below the x-axis.

f' is less than 0 means that f is decreasing there.

Since we are looking for relative maximum(s), we are looking for when the graph of f switches from increasing to decreasing. That forms something that looks like this '∩' sort of.

This means we are looking for when f' switches from positive to negative. At that switch point is where we have the relative maximum occurring at.

Looking at the graph the switch points are at x=0, x=1, and x=2.

At x=0, we have f' is less than 0 before x=0 and that f' is greater than 0 after x=0.  That means f is decreasing to increasing here. There would be a relative minimum at x=0.

At x=1, we have f' is greater than 0 before x=1 and that f' is less than 0 after x=1. That means f is increasing to decreasing here. There would be a relative maximum at x=1.

At x=2, we have f' is less than 0 before x=2 and that f' is greater than 0 after x=2. That means f is decreasing to increasing here. There would be a relative minimum at x=2.

Conclusion:

* Relative minimums at x=0 and x=2

* Relative maximums at x=1

3 0
2 years ago
What is the distance between point A (−1, 3) and point B (−7, 3) ?
malfutka [58]

Answer:

6

Step-by-step explanation:

I used the formula  d=√((x_2-x_1)²+(y_2-y_1)²), plugged in the numbers and solved and got 6 units.

8 0
3 years ago
Vladimir says that the equation of the line that passes through points (negative 5, negative 3) and (10, 9) is y = four-fifths x
love history [14]

Answer:

Vladimir and Robyn both are correct.

Step-by-step explanation:

Let us check whether the points (-5,-3) and (10,9) are on the line y = \frac{4}{5}x + 1 or not.

The equation of the straight line passing through the given points (-5,-3) ans (10,9) is \frac{y - 9}{9 + 3} = \frac{x - 10}{10 + 5}

⇒ 5(y - 9) = 4(x - 10)

⇒ 5y = 4x + 5

⇒  y = \frac{4}{5}x + 1 .............. (1)

So, Vladimir is correct.

Now, Robyn says that the line passes through the points (-10,-7) and (-15,-11).

Then, both of the points satisfy the equation (1).

Therefore, Vladimir and Robyn both are correct. (Answer)

4 0
2 years ago
Read 2 more answers
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