-43/204
Step-by-step explanation:
−5/12 × 17/17 + 7/34 × 6/6 =
= −85/204 + 42/204
= −85 + 42/204
= −43/204
The distance of PQ is sqrt 40 or ≈ 6.32
Answer:
Step-by-step explanation:
One hundred sixty thousand fifty two
The work required to stretch the spring is 350J.
<h3>Hooke's Law</h3>
This law can be written by the formula: F=kx, where:
F= elastic force (N)
k= spring constant (N/m)
x= linear displacement (m)
<h3>Spring Work</h3>
For finding the spring work in J, you should apply the formula
, where:
W= work (J)
k= spring constant (N/m)
x= difference between the linear displacements (m)
The question gives:
x=5 cm=0.05m requires a force of 1.4N
x=8 cm =0.08m
- Step 1 - First, you should find the spring constant from Hooke's law, for x=5 cm and F=1.4N.

- Step 2 - Now you can apply the formula for spring work.

Read more about the spring work here:
brainly.com/question/3317535