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lord [1]
3 years ago
9

Why is it more accurate to say that the concentration of a solution of acetic acid is 0.01 f rather than 0.01 m?

Chemistry
2 answers:
Mandarinka [93]3 years ago
5 0

Answer:

The formal concentration accounts for the moles of the original chemical formula into the solution rather than the concentration of the species that actually exist in solution which is accounted for by the molarity.

Explanation:

Hello,

In this case, the difference between formal and molar units of concentration  lies on the fact that the formal concentration accounts for the moles of the original chemical formula into the solution rather than the concentration of the species that actually exist in solution which is accounted for by the molarity. In such a way, since acetic acid is partially dissociated, formality better explains there are 0.01 moles of acetic acid added to the solution including both the non-dissociated and dissociated constituents. However, molarity just accounts for the 0.01 moles of acetic acid that could or could not have been dissociated into the solution.

As you see, this is just a by concept difference, as they lead to suitable calculations.

Best regards.

olasank [31]3 years ago
4 0

A 1 F solution stands 1 formula unit per litre and 0.01 F describes the concentration of solution with no deliberation for the real form of existence of species.

Molarity is defined as the ratio of moles of solute to the volume of solution in litres and it is used to describe formality. For accuracy, it is essential to expressed molarity of each species. In case of acetic acid, the molarity of acetic acid molecules is less than 0.01 M due to dissociation.

Thus, it is more precise to say that the concentration of a solution of acetic acid is 0.01 F instead of 0.01 M.

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In a lab experiment 80.0 g of ammonia [NH3] and 120 g of oxygen are placed in a reaction vessel. At the end of the reaction 72.2
valentinak56 [21]

The percent yield of the reaction : 89.14%

<h3>Further explanation</h3>

Reaction of Ammonia and Oxygen in a lab :

<em>4 NH₃ (g) + 5 O₂ (g) ⇒ 4 NO(g)+ 6 H₂O(g)</em>

mass NH₃ = 80 g

mol NH₃ (MW=17 g/mol):

\dfrac{80}{17}=4.706

mass O₂ = 120 g

mol O₂(MW=32 g/mol) :

\tt \dfrac{120}{32}=3.75

Mol ratio of reactants(to find limiting reatants) :

\tt \dfrac{4.706}{4}\div \dfrac{3.75}{5}=1.1765\div 0.75\rightarrow O_2~limiting~reactant(smaller~ratio)

mol of H₂O based on O₂ as limiting reactants :

mol H₂O :

\tt \dfrac{6}{5}\times 3.75=4.5

mass H₂O :

4.5 x 18 g/mol = 81 g

The percent yield :

\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{72.2}{81}\times 100\%=89.14\%

6 0
3 years ago
What is an alkaline earth metal that has 5 shells?
brilliants [131]

Answer:

The elements in the alkaline earth metals group; beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra), have two electrons in their outer electronic shell.

Explanation:

3 0
3 years ago
Read 2 more answers
In the chemical reaction: NaOH (s) + H2O Na+ (aq) + OH- (aq), which substance (or substances) is in solution? A. Na+ (aq) only B
bonufazy [111]

Answer:

in a chemical reaction of NaOH with H2O, after NaOH is completely disassociated, we will find Na+ and OH- ions in the solution. (option C).

Explanation:

In a reaction where NaOH is added to H2O.

NaOH is considered a strong base, this means that in an aqueous solution ( in water) it's  able to completely disassociate in ions.

There will not remain any NaOH in the solution. This means option D is not correct.

The ions in which NaOH will disassociate are : NaOH → Na+ + OH-

These ions we will find in the solution.

Not only Na+ because NaOH is a strong base, so there will be a lot of OH- ions as well in solution.

This means in a chemical reaction of NaOH with H2O, after NaOH is completely disassociated, we will find Na+ and OH- ions in the solution.

3 0
2 years ago
The poisonous gas hydrogen sulfide, H2S, can be neutralized with a base such as sodium hydroxide,
mariarad [96]

Answer:

It's not correct. For balancing, we need to put the coefficients in the molecule, not in the athom. Because if you do this, you're creating another molecule, instead of a balacing, for which the reaction may not happen - but anyway, it would be another reaction.

The correct balacing is:

2NaOH + 1H2S → 1Na2S + 2H2O

Explanation:

Look: Na2OH does not even exist. OH has only one free link, so he can't - in normal conditions - make another one with any athom. That's why we should write 2NaOH instead of Na2OH. The first means "2 mols of NaOH".

4 0
3 years ago
How does energy in a nuclear reaction get created?
nasty-shy [4]
My answer -

A nuclear reactor produces and controls the release of energy from splitting the atoms of uranium. 

Uranium-fuelled nuclear power is a clean and efficient way of boiling water to make steam which drives turbine generators. Except for the reactor itself, a nuclear power station works like most coal or gas-fired power stations.


P.S

Happy to help you have an AWESOME!!! day ^-^


7 0
2 years ago
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