After 1 half life its half the element
after 2 hl its quarter remaining
after 3 hl its half the quarter which is 1 eighth
after 3 half lifes
The given question is incomplete. The complete question is:
Suppose a current of 0.920 A is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for 47.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.
Answer: 0.0484 g
Explanation:
where Q= quantity of electricity in coloumbs
I = current in amperes = 0.920 A
t= time in seconds = 47.0 sec

96500 Coloumb of electricity electrolyzes 1 mole of Ag
43.24 C of electricity deposits =
of Ag
Thus the mass of pure silver deposited on a metal object made into the cathode of the cell is 0.0484 g
Answer:
a frisbee flaying in the air
Explanation:
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;

Where;
- K.E represents kinetic energy measured in Joules.
- M represents mass measured in kilograms.
- V represents velocity measured in metres per seconds square.
Hence, an example of kinetic energy at work is a frisbee flaying in the air because it would possess energy due to its motion in the air.
Answer:
a. Molarity= 
b. Molality= 
Explanation:
Hello,
In this case, given the information about the aniline, whose molar mass is 93g/mol, one could assume the volume of the solution is just 200 mL (0.200 L) as no volume change is observed when mixing, therefore, the molarity results:

Moreover, the molality:

Best regards.
Kilo
hecto
deca
base
deci
centi
milli
king Hector died by drinking chocolate milk
25 milligrams equal 0.025 grams