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wolverine [178]
3 years ago
15

Combining Boyle's law and Charles' law forms one presure-temperature-volume relationship and holds the mass of the gas constant.

Which equation represents the relationship of the combined gas law?
A) (P1/T1)=(P2/T2)
B) (P1/n1)=(P2/n2)
C) (P1V1/T1)=(P2V2/T2)
D) P1V1=P2V2
Chemistry
1 answer:
Troyanec [42]3 years ago
5 0

Option C

Explanation:

Boyles law states that pressure is in inverse proportion with volume for a gas. This can be represented by the equation PV=k, where P is the pressure, V is the volume and k is a constant.

Charles law states that volume is in direct proportion with to temperature of the gas. This can be represented by the equation V/T=k, where T stands for temperature, V stands for volume and k represents a constant.

Combining the equations for Charles and Boyles law we get

PV/T = k,   here k represents the constant value.

If we have P1, V1, T1 and P2 V2 and T2 representing the pressure of gas, volume of gas and the temperature of gas in 2 different conditions, then as per the above laws

P1V1/T1 = k and P2V2/T2 = k

Since both are equal to the same constant k, we have  P1V1/T1=P2V2/T2

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Compare the root mean square speeds of O2 and UF6 at 65 degree Celsius
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<h3>Answer:</h3>

The root mean square speeds of O₂ and UF₆ is 513m/s and 155 m/s respectively.

<h3>Solution and Explanation:</h3>
  • To find how fast molecules or particles of gases move at a particular temperature, the root  mean square speed is calculated.
  • Root mean square speed of a gas is calculated by using the formula;

       Root mean square=\sqrt{ \frac{3RT}{M}

       Where R is the molar gas constant, T is the temperature and M is the molar mass of gas in Kg.

<h3>Step 1: Root mean square speed from O₂</h3>

Molar mass of Oxygen is 32.0 g/mol or 0.032 kg/mol

Temperature = 65 degrees Celsius or 338 K

Molar gas constant = 8.3145 J/k.mol

Root mean square speed = \sqrt\frac{(3)(8.3145)(338K)}{0.032}

                                        = 513.289 m/s

<h3>Step 2: Root mean square speed of UF₆   </h3>

The molar mass of UF₆ is 352 g/mol or 0.352 kg/mol        

Root mean square speed = \sqrt\frac{(3)(8.3145)(338K)}{0.352}

                                                 = 154.762m/s

Therefore; the root mean square speeds of O₂ and UF₆ is 513m/s and 155 m/s respectively.

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