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wolverine [178]
3 years ago
15

Combining Boyle's law and Charles' law forms one presure-temperature-volume relationship and holds the mass of the gas constant.

Which equation represents the relationship of the combined gas law?
A) (P1/T1)=(P2/T2)
B) (P1/n1)=(P2/n2)
C) (P1V1/T1)=(P2V2/T2)
D) P1V1=P2V2
Chemistry
1 answer:
Troyanec [42]3 years ago
5 0

Option C

Explanation:

Boyles law states that pressure is in inverse proportion with volume for a gas. This can be represented by the equation PV=k, where P is the pressure, V is the volume and k is a constant.

Charles law states that volume is in direct proportion with to temperature of the gas. This can be represented by the equation V/T=k, where T stands for temperature, V stands for volume and k represents a constant.

Combining the equations for Charles and Boyles law we get

PV/T = k,   here k represents the constant value.

If we have P1, V1, T1 and P2 V2 and T2 representing the pressure of gas, volume of gas and the temperature of gas in 2 different conditions, then as per the above laws

P1V1/T1 = k and P2V2/T2 = k

Since both are equal to the same constant k, we have  P1V1/T1=P2V2/T2

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Explanation:

We are given:

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In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, =\frac{12}{44}\times 18.59=5.07g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

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Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.422}{0.422}=1

For H =\frac{0.862}{0.422}=2

The ratio of C : H = 1: 2

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The empirical weight of CH_2 = 1(12)+2(1)= 14 g.

The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4

The molecular formula will be=4\times CH_2=C_4H_8

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