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wolverine [178]
3 years ago
15

Combining Boyle's law and Charles' law forms one presure-temperature-volume relationship and holds the mass of the gas constant.

Which equation represents the relationship of the combined gas law?
A) (P1/T1)=(P2/T2)
B) (P1/n1)=(P2/n2)
C) (P1V1/T1)=(P2V2/T2)
D) P1V1=P2V2
Chemistry
1 answer:
Troyanec [42]3 years ago
5 0

Option C

Explanation:

Boyles law states that pressure is in inverse proportion with volume for a gas. This can be represented by the equation PV=k, where P is the pressure, V is the volume and k is a constant.

Charles law states that volume is in direct proportion with to temperature of the gas. This can be represented by the equation V/T=k, where T stands for temperature, V stands for volume and k represents a constant.

Combining the equations for Charles and Boyles law we get

PV/T = k,   here k represents the constant value.

If we have P1, V1, T1 and P2 V2 and T2 representing the pressure of gas, volume of gas and the temperature of gas in 2 different conditions, then as per the above laws

P1V1/T1 = k and P2V2/T2 = k

Since both are equal to the same constant k, we have  P1V1/T1=P2V2/T2

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28. How many formula units are found in 0.250 moles of potassium nitrate?
Soloha48 [4]

Answer:

\boxed {\boxed {\sf B. \ 1.5 *10^{23} \ formula \ units}}

Explanation:

1 mole of any substance contains the same number of particles. The particles can vary (atoms, molecules, formula units), but there are always 6.022*10²³ particles. In this case, the particles are formula units of potassium nitrate or KNO₃.

Let's create a ratio.

\frac {6.022*10^{23} \ formula \ units  \ KNO_3}{1 \ mol \ KNO_3}

Since we are trying to find the formula units in 0.250 moles, we multiply by that number.

0.250 \ mol \ KNO_3 *\frac {6.022*10^{23} \ formula \ units  \ KNO_3}{1 \ mol \ KNO_3}

The units of moles of potassium nitrate cancel.

0.250  *\frac {6.022*10^{23} \ formula \ units  \ KNO_3}{1 }

The denominator of 1 can be ignored, so we can make a simple multiplication problem.

0.250  *{6.022*10^{23} \ formula \ units  \ KNO_3}

1.5055 * 10^{23} \ formula \ units \ KNO_3

If we round to the nearest tenth, the 0 in the hundredth place tells us to leave the 5 in the tenth place.

1.5 *10^{23} \ formula \ units \ KNO_3

0.250 moles of potassium nitrate is approximately equal to 1.5*10²³ formula units of potassium nitrate and choice B is correct.

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3 years ago
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Assoli18 [71]
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8 0
3 years ago
How many formula units are contained in 2.35mol of Iron (III) Oxide
konstantin123 [22]
Remember, 1 mole= 6.022x10^23 atoms, molecules, or formula units.

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The overall equation for the cellular respiration of glucose is C6H12O6 + 6 O2 → 6 CO2 + 6 H2O + energy. C5H12O6 + 6 O2 → 5 CO2
olga55 [171]

Answer:

The answer to your question is: first option.

Explanation:

C6H12O6 + 6 O2 → 6 CO2 + 6 H2O + energy.  This option is correct, 1 molecule of glucose reacts with 6 molecules of oxygen and produces 6 molecules of carbon dioxide, six molecules of water and energy.

C5H12O6 + 6 O2 → 5 CO2 + 6 H2O + energy. This option is incorrect because glucose has 6 carbons not five.

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