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Flura [38]
3 years ago
9

PLEASE HELP ME

Chemistry
2 answers:
seropon [69]3 years ago
7 0
20m x 100kg = 200j
If you are calculating potential energy you want to do ( height x weight)
In this case our height is the the bell which is 20 m high and our bell weighs 100kg so you would just multiply. Hope this helps
eimsori [14]3 years ago
5 0
PE=MGH
(Mass)(Gravity)(Height)

Pe=(100kg)(9.81 m/s)(20m)
Pe=19,620 J
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lions [1.4K]

<u>Answer:</u> The equilibrium concentration of COF_2 is 0.332 M

<u>Explanation:</u>

We are given:

Initial concentration of COF_2 = 2.00 M

The given chemical equation follows:

                2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)

<u>Initial:</u>          2.00

<u>At eqllm:</u>     2.00-2x          x      x

The expression of K_c for above equation follows:

K_c=\frac{[CO_2][CF_4]}{[COF_2]^2}

We are given:

K_c=6.30

Putting values in above expression, we get:

6.30=\frac{x\times x}{(2.00-2x)^2}\\\\x=0.834,1.25

Neglecting the value of x = 1.25 because equilibrium concentration of the reactant will becomes negative, which is not possible

So, equilibrium concentration of COF_2=(2.00-2x)=[2.00-(2\times 0.834)]=0.332M

Hence, the equilibrium concentration of COF_2 is 0.332 M

4 0
3 years ago
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user100 [1]
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3 years ago
Which element above has 6 protons in its nucleus?
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B. carbon because it's atomic number is 6
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3 years ago
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Predict the decay process and write the nuclear equation of Cf- 255
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curium

−

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Answer:

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The law of definite proportions states that atoms combine in a molecule in a specific molar ratio or specific stoichiometry. For example, it's proved that regardless of the quantity we take, two hydrogen atoms always combine with one oxygen atom to form a water molecule.

Similarly, ionic substances follow the same pattern. Since the net charge of ionic salts should be equal to 0 and each element has a definite number of valence electrons in its shell all the time, the ions combine in a way, so that cations balance the charge of anions.

Essentially, the law of definite proportions is applicable and will be applicable in the future, since we know that each element has a fixed number of valence electrons in its ground state.

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