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Snezhnost [94]
3 years ago
13

When hydrogen is burned in oxygen to form water, the composition of water formed does not depend on the amount of oxygen reacted

. interpret this in terms of the law of definite proportion?
Chemistry
2 answers:
VLD [36.1K]3 years ago
4 0
Law of Definite Proportions states that a compound is composed of the same ratio of elements present. The formation of water has a reaction:

H2 + 1/2 O2 = H2O

The limiting reactant would be the element with the least ratio of molar mass to stoichiometric coefficient, and that would be H2, not O2.
Vedmedyk [2.9K]3 years ago
4 0

Answer:  

Explanation:  Law of Definite Proportions state that in a chemical compound, the constituent element will always exist in a fixed ratio which does not depend on the source of preparation.

So when hydrogen is burned in oxygen to form water, the composition of water formed does not depend on the oxygen but it depends on the hydrogen itself.

H_{2}O + 1/2 O_{2} \rightarrow H_{2}O

Thus the reaction usually depends on the limiting reagent ad hence , in the above reaction, hydrogen is the limiting reagent. Thus the reaction will depend on the hydrogen, not on oxygen.

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What is a scientific question?
Elena L [17]

Answer:

O c. One that is answered through observation

I used process of elminations so

Explanation:

One that everyone agrees one doesnt mean it's accurate.

Only the one that scientists ask doesnt make sense

One that never changes and One that is answered through observation.... So C

5 0
4 years ago
What is the melting point of water?
o-na [289]
 the melting point of water is 32 degrees Fahrenheit , 0 degrees Celsius. <span />
6 0
4 years ago
The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calc
jek_recluse [69]

Answer: K_{sp}=1.25\times 10^{-14}

pK_{sp}=13.90

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}  

The equation for the ionization of magnesium phosphate is given as:

Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}

 When the solubility of Mg_3(PO_4)_2 is S moles/liter, then the solubility of Mg^{2+} will be 3S moles\liter and solubility of PO_4^{3-} will be 2S moles/liter.

Thus S = 0.173 g/L or \frac{0.173g/L}{262.8g/mol}=0.00065mol/L

K_{sp}=(3S)^3\times (2S)^2

K_{sp}=108S^5

K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}

pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90

5 0
3 years ago
How much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh
Sever21 [200]

Answer:

13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

Volume of the base (Vb) = 39mL

Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

6 x Va / 2 x 39 = 1/1

Cross multiply to express in linear form

6 x Va = 2 x 39

Divide both side by 6

Va = (2 x 39)/6

Va = 13mL

Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL

5 0
3 years ago
I need help I can't chose between A or D
djyliett [7]
That’s a hard one, but honestly i would go with a.
7 0
4 years ago
Read 2 more answers
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