Can someone help me with this?!
1 answer:
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Answer:
C
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange 6x + 10y = 8 into this form by subtracting 6x from both sides
10y = - 6x + 8 ( divide all terms by 10 )
y = - x +
← in slope- intercept form
with slope m = - → C
Answer:
Option B
The measure of angle b is 75°
Step-by-step explanation:
Method 1
we know that
In a inscribed quadrilateral, the opposite angles are supplementary
so
∠a+60°=180° ------> equation A
∠b+105°=180° -----> equation B
To find the measure of angle b solve the equation B
∠b+105°=180°
Subtract 105° both sides
∠b+105°-105°=180°-105°
∠b=75°
Method 2
see the attached figure with letters to better understand the problem
we know that
The inscribed angle measures half that of the arc comprising
so
∠105°=(1/2)[arc ADC]
arc ADC=2*105°=210°
<em><u>Find the measure of arc ABC</u></em>
we know that
arc ABC+arc ADC=360° -----> by complete circle
arc ABC=360°-210°=150°
<u><em>Find the measure of inscribed angle b</em></u>
∠b=(1/2)[arc ABC]
substitute
∠b=(1/2)[arc 150°]=75°
