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Stella [2.4K]
2 years ago
13

Help me WILL PICK BRAINLIEST

Mathematics
2 answers:
Elanso [62]2 years ago
8 0

n is 7 :] ...

Step-by-step explanation:

pls mark brainlest

marin [14]2 years ago
8 0

Answer:

n = -8

Step-by-step explanation:

5 (-8 - 4) = -60

5 (-12) = -60

-60 = -60

Do it on any calculator that's what you'll get

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Write each equation in standard form. y=0.5x+3
dimulka [17.4K]
The equation in standard form is 0.5x-y=-3.
6 0
2 years ago
Factor: a^2+b^2–c^2+2ab
Kruka [31]

Rearrange the polynomial:

a^2–2ab+b^2 - c^2

((a-b)(a-b))-c^2

(a-b)^2-c^2

Set x =a-b and y=c. The formula becomes

x^2-y^2

factoring this polynomial, we get

(x+y)(x-y)

Substituting back, we get:

(a+b+c)(a+b-c)

Let’s multiply it out to check:

A^2 -ab ac

- ab B^2 -bc

-ac bc -c^2

6 0
3 years ago
Read 2 more answers
Help me with this question​
Arturiano [62]
A) 60q/12
b) set ^ this equation equal to the one on the paper, move the variable to one side, and the rest should be easy from there
c) he loses profits
8 0
2 years ago
Geometry!!!!!!!!!!!!!!!!!!!!!!!!
Stella [2.4K]

<u>Given</u>:

Given that O is the center of the circle.

The radius of the circle is 3 m.

The measure of ∠AOB is 30°

We need to determine the length of the major arc ACB

<u>Measure of major ∠AOB:</u>

The measure of major angle AOB can be determined by subtracting 360° and 30°

Thus, we have;

Major \ \angle AOB=360-30

Major \ \angle AOB=330^{\circ}

Thus, the measure of major angle is 330°

<u>Length of the major arc ACB:</u>

The length of the major arc ACB can be determined using the formula,

<u></u>m \widehat{ACB}=(\frac{\theta}{360})2 \pi r<u></u>

Substituting r = 3 and \theta=330, we get;

m \widehat{ACB}=(\frac{330}{360})2 \pi (3)

m \widehat{ACB}=\frac{1980}{360}\pi

m \widehat{ACB}=5.5 \pi

Thus, the length of the major arc ACB is 5.5π m

8 0
3 years ago
ABCD is a trapezium AD and BC are parallel
Orlov [11]

Part (a)

<h3>Answer:  12.1</h3>

-----------------------

Work Shown:

We'll apply the sine rule since we have a known opposite side of AB = 10 and an unknown hypotenuse we want to find BD.

Focus on triangle ABD

sin(angle) = opposite/hypotenuse

sin(D) = AB/BD

sin(56) = 10/x

x*sin(56) = 10

x = 10/sin(56)

x = 12.062179

x = 12.1

Make sure your calculator is in degree mode.

===================================================

Part (b)

<h3>Answer:  15.1</h3>

-----------------------

Work Shown:

Draw an xy coordinate grid.

Place point A at the origin (0,0).

Point B is 10 units above this, so B is at (0,10).

Point C is at (18,10) since we move 18 units to the right of B.

Point D is at approximately (6.745085, 0). The 6.745085 is from solving tan(56) = 10/x for x.

Refer to the diagram below.

Apply the distance formula for the points C and D.

C = (x_1,y_1) = (18,10)\\\\D = (x_2,y_2) \approx (6.745085,10)\\\\

d = \text{ distance from C to D}\\\\d = \sqrt{ (x_1-x_2)^2+(y_1-y_2)^2}\\\\d \approx \sqrt{ (18-6.745085)^2+(10-0)^2}\\\\d \approx \sqrt{ 226.673112 }\\\\d \approx 15.055667\\\\d \approx 15.1\\\\

Segment CD is roughly 15.1 cm long.

3 0
3 years ago
Read 2 more answers
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