The equation in standard form is 0.5x-y=-3.
Rearrange the polynomial:
a^2–2ab+b^2 - c^2
((a-b)(a-b))-c^2
(a-b)^2-c^2
Set x =a-b and y=c. The formula becomes
x^2-y^2
factoring this polynomial, we get
(x+y)(x-y)
Substituting back, we get:
(a+b+c)(a+b-c)
Let’s multiply it out to check:
A^2 -ab ac
- ab B^2 -bc
-ac bc -c^2
A) 60q/12
b) set ^ this equation equal to the one on the paper, move the variable to one side, and the rest should be easy from there
c) he loses profits
<u>Given</u>:
Given that O is the center of the circle.
The radius of the circle is 3 m.
The measure of ∠AOB is 30°
We need to determine the length of the major arc ACB
<u>Measure of major ∠AOB:</u>
The measure of major angle AOB can be determined by subtracting 360° and 30°
Thus, we have;


Thus, the measure of major angle is 330°
<u>Length of the major arc ACB:</u>
The length of the major arc ACB can be determined using the formula,
<u></u>
<u></u>
Substituting r = 3 and
, we get;



Thus, the length of the major arc ACB is 5.5π m
Part (a)
<h3>Answer: 12.1</h3>
-----------------------
Work Shown:
We'll apply the sine rule since we have a known opposite side of AB = 10 and an unknown hypotenuse we want to find BD.
Focus on triangle ABD
sin(angle) = opposite/hypotenuse
sin(D) = AB/BD
sin(56) = 10/x
x*sin(56) = 10
x = 10/sin(56)
x = 12.062179
x = 12.1
Make sure your calculator is in degree mode.
===================================================
Part (b)
<h3>
Answer: 15.1</h3>
-----------------------
Work Shown:
Draw an xy coordinate grid.
Place point A at the origin (0,0).
Point B is 10 units above this, so B is at (0,10).
Point C is at (18,10) since we move 18 units to the right of B.
Point D is at approximately (6.745085, 0). The 6.745085 is from solving tan(56) = 10/x for x.
Refer to the diagram below.
Apply the distance formula for the points C and D.


Segment CD is roughly 15.1 cm long.