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Reil [10]
2 years ago
9

Help me with this question​

Mathematics
1 answer:
Arturiano [62]2 years ago
8 0
A) 60q/12
b) set ^ this equation equal to the one on the paper, move the variable to one side, and the rest should be easy from there
c) he loses profits
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the number y of oranges is used to make c pints of orange juice if represented by the equation y=8x. Graph the equation
abruzzese [7]

Answer:

y=8x

8x=y

Step-by-step explanation:

8 0
2 years ago
Water is poured into container A so that it’s 2/3 full.
tigry1 [53]

Step-by-step explanation:

Volume of Container A

= (8cm)(8cm)(12cm) = 768cm³.

Volume of water = 2/3 * Volume of Container A

= (2/3) * 768cm³ = 512cm³.

Base Area of Container B

= (10cm)(10cm) = 100cm².

Hence Depth of water in Container B

= 512cm³ / 100cm² = 5.12cm.

8 0
3 years ago
Determine the value of z in the figure answers: z = 50° z = 45° z = 10° z = 30°
ycow [4]

Answer:

z = 10°

Step-by-step explanation:

Since the two sides are equal, the two base angles have to be equal

That means that 5z and 130 form a straight line and add to 180 degrees

5z+130 = 180

Subtract 130 from each side

5z = 50

Divide by 5

5z/5 = 50/5

z=10

3 0
3 years ago
Can some one friend me plz
Alona [7]

Answer: I didn't understand

4 0
3 years ago
The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
3 years ago
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