Answer:
is high as 100 degrees c
Explanation:
due to high heat gas expands fast than normal
Answer: 80m
Explanation:
Distance of balloon to the ground is 3150m
Let the distance of Menin's pocket to the ground be x
Let the distance between Menin's pocket to the balloon be y
Hence, x=3150-y------1
Using the equation of motion,
V^2= U^s + 2gs--------2
U= initial speed is 0m/s
g is replaced with a since the acceleration is under gravity (g) and not straight line (a), hence g is taken as 10m/s
40m/s is contant since U (the coin is at rest is 0) hence V =40m/s
Slotting our values into equation 2
40^2= 0^2 + 2 * 10* (3150-y)
1600 = 0 + 63000 - 20y
1600 - 63000 = - 20y
-61400 = - 20y minus cancel out minus on both sides of the equation
61400 = 20y
Hence y = 61400/20
3070m
Hence, recall equation 1
x = 3150 - 3070
80m
I hope this solve the problem.
Answer:
23
21.7391304348 m
Explanation:
L = Initial length = 500 m
= Change in temperature = 40-(-35)
= Coefficient of thermal expansion = 
Change in length is given by
The change in length is 0.45 m
The number of joints would be
The number of joints is 23
Each bridge section length would be
The length of each bridge section would be 21.7391304348 m
The kilogram is the SI unit of mass and it is the almost universally used standard mass unit. The associated SI unit of force and weight is the Newton, with 1 kilogram weighing 9.8 Newtons under standard conditions on the Earth's surface.
Answer:
The maximum value of θ that will cause the block to remain stationary on the inclined surface is 21.8°
Explanation:
Given;
coefficient of static friction, μ = 0.4
for the block to remain stationary on the inclined plane, force pushing the block upward must be equal to the force acting downwards.
μR = mgsinθ
μmgcosθ = mgsinθ
μcosθ = sinθ
μ = sinθ/cosθ
μ = tanθ
θ = tan⁻¹(0.4) = 21.8°
Therefore, the maximum value of θ that will cause the block to remain stationary on the inclined surface is 21.8°
