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igor_vitrenko [27]
3 years ago
14

What are the units for mass and weight?

Physics
2 answers:
Arlecino [84]3 years ago
8 0

Answer:

pounds or lbs

Explanation:

weight is measured in pounds.

Luda [366]3 years ago
6 0

The kilogram is the SI unit of mass and it is the almost universally used standard mass unit. The associated SI unit of force and weight is the Newton, with 1 kilogram weighing 9.8 Newtons under standard conditions on the Earth's surface.

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Describe where each subatomic particle is found in an atom.
zysi [14]
The last column in the table lists the location of the three subatomic particles.Protons<span> and </span>neutrons<span> are located in the nucleus, a dense central core in the middle of the atom, while the electrons are located outside the nucleus.</span>
7 0
3 years ago
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Ya'll please I need help only on #5 Its confusing<br><br> (Grade 10 Physics, Potential Energy)
skad [1K]

Answer:

Potential energy = work done on the spring

= Force x displacement

= 15 N x 0.025 m

= 0.375 J

3 0
3 years ago
An engineer designs a roller coaster so that a car travels horizontally for 162 ft, then climbs 137 ft at an angle of 31.0° abov
Zielflug [23.3K]

Answer:

Explanation:

We know that

Δr = r₁ - r₀

r₀ = 0 i + 0 j

r₁ = (162+137*Cos(31º)+137*Cos(-48º)) i + (0+137*Sin(31º)+137*Sin(-48º)) j = (371.1028 i - 31.2506 j) ft

Δr = r₁ - r₀ = (371.1028 i - 31.2506 j) - (0 i + 0 j) = (371.1028 i - 31.2506 j) ft

Magnitude:

Δr = √((371.1028)²+(-31.2506)²) = 372.4163 ft

Angle:

tan θ = (- 31.2506 / 371.1028) = -0.0839   ⇒   θ = tan⁻¹(-0.0839) = - 4.8135º

(below the horizontal).

8 0
4 years ago
What is the volume in liters of the basketball?
babymother [125]

he basket ball diameter used by NBA men players is around 9.55 inches

So diameter = 9.55 inch = 0.243 m

So radius of basket ball = 0.1215 m

Volume , V=\frac{4}{3} \pi r^3

V = \frac{4}{3}* \pi *0.1215^3=0.0075 m^3=7.5 L

So volume of basket ball used by men NBA players = 7.5 L

   

5 0
3 years ago
Read 2 more answers
Colonel John P. Stapp, USAF, participated in studying whether a jet pilot could survive emergency ejection. On March 19, 1954, h
PolarNik [594]

Answer:

(a) a = - 201.8 m/s²

(b) s = 197.77 m

Explanation:

(a)

The acceleration can be found by using 1st equation of motion:

Vf = Vi + at

a = (Vf - Vi)/t

where,

a = acceleration = ?

Vf = Final Velocity = 0 m/s (Since it is finally brought to rest)

Vi = Initial Velocity = (632 mi/h)(1609.34 m/ 1 mi)(1 h/ 3600 s) = 282.53 m/s

t = time = 1.4 s

Therefore,

a = (0 m/s - 282.53 m/s)/1.4 s

<u>a = - 201.8 m/s²</u>

<u></u>

(b)

For the distance traveled, we can use 2nd equation of motion:

s = Vi t + (0.5)at²

where,

s = distance traveled = ?

Therefore,

s = (282.53 m/s)(1.4 s) + (0.5)(- 201.8 m/s²)(1.4 s)²

s = 395.54 m - 197.77 m

<u>s = 197.77 m</u>

6 0
3 years ago
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