The last column in the table lists the location of the three subatomic particles.Protons<span> and </span>neutrons<span> are located in the nucleus, a dense central core in the middle of the atom, while the electrons are located outside the nucleus.</span>
Answer:
Potential energy = work done on the spring
= Force x displacement
= 15 N x 0.025 m
= 0.375 J
Answer:
Explanation:
We know that
Δr = r₁ - r₀
r₀ = 0 i + 0 j
r₁ = (162+137*Cos(31º)+137*Cos(-48º)) i + (0+137*Sin(31º)+137*Sin(-48º)) j = (371.1028 i - 31.2506 j) ft
Δr = r₁ - r₀ = (371.1028 i - 31.2506 j) - (0 i + 0 j) = (371.1028 i - 31.2506 j) ft
Magnitude:
Δr = √((371.1028)²+(-31.2506)²) = 372.4163 ft
Angle:
tan θ = (- 31.2506 / 371.1028) = -0.0839 ⇒ θ = tan⁻¹(-0.0839) = - 4.8135º
(below the horizontal).
he basket ball diameter used by NBA men players is around 9.55 inches
So diameter = 9.55 inch = 0.243 m
So radius of basket ball = 0.1215 m
Volume , 
So volume of basket ball used by men NBA players = 7.5 L
Answer:
(a) a = - 201.8 m/s²
(b) s = 197.77 m
Explanation:
(a)
The acceleration can be found by using 1st equation of motion:
Vf = Vi + at
a = (Vf - Vi)/t
where,
a = acceleration = ?
Vf = Final Velocity = 0 m/s (Since it is finally brought to rest)
Vi = Initial Velocity = (632 mi/h)(1609.34 m/ 1 mi)(1 h/ 3600 s) = 282.53 m/s
t = time = 1.4 s
Therefore,
a = (0 m/s - 282.53 m/s)/1.4 s
<u>a = - 201.8 m/s²</u>
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(b)
For the distance traveled, we can use 2nd equation of motion:
s = Vi t + (0.5)at²
where,
s = distance traveled = ?
Therefore,
s = (282.53 m/s)(1.4 s) + (0.5)(- 201.8 m/s²)(1.4 s)²
s = 395.54 m - 197.77 m
<u>s = 197.77 m</u>
