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hram777 [196]
3 years ago
12

How can a tennis ball and a bowling ball have the same momentum ?

Physics
1 answer:
Verdich [7]3 years ago
7 0
C would be the right answer edu
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A 700 kg racecar slowed from 30 m/s to 15 m/s. What was the change in momentum?
xxMikexx [17]
Momentum equation is

change in momentum = mass•initial velocity•final velocity

so....

p=700(15) because your initial is 30, and your final in 15, so you subtract! hope that helped!
8 0
3 years ago
1 nanometer is equals to?
netineya [11]

1×10^_19 meters

hope it helps you!!!!!

3 0
4 years ago
Read 2 more answers
archaeologists use radioactive decay of an isotope of the element because it has a fairly short half-life and is found in anythi
natulia [17]

Archaeologists use radioactive decay of an isotope of the element <u>carbon.</u> Because it has a fairly short half-life, and is found in anything that was once living.

<h3>What is radioactivity?</h3>

The act of producing radiation spontaneously is known as radioactivity. This is accomplished by an unstable atomic nucleus that want to give up some energy in order to move to a more stable form.

Archaeologists use radioactive decay of an isotope of the element <u>carbon.</u> Because it has a fairly short half-life, and is found in anything that was once living.

Hence, <u>carbon</u> is used the correct answer for the blank.

To learn more about the radioactivity, refer  to the link;

brainly.com/question/1770619

#SPJ1

7 0
2 years ago
which obstacle to problem solving involves arriving at a solution based on your preconceptions and ignoring any evidence that go
White raven [17]

Answer:

confirmation bias

Explanation:

the tendency to interpret new evidence as confirmation of one's existing beliefs or theories in a way that affirms one's prior beliefs or hypotheses.

5 0
4 years ago
What decibel reading corresponds to a pressure amplitude of 0.2 W/m^2?
horsena [70]

I  = pressure amplitude given = 0.2 W/m²

dB = decibel reading

decibel reading from the pressure amplitude is given as

dB = 10 log₁₀ (I/10⁻¹²)

inserting the values in the above equation

dB = 10 log₁₀ (0.2/10⁻¹²)

dB = 10 log₁₀ (2 x 10⁻¹/10⁻¹²)

dB = 10 log₁₀ (2 x 10⁻¹.10¹²)

dB = 10 log₁₀ (2 x 10¹²⁻¹)

dB = 10 log₁₀ (2 x 10¹¹)

dB = 113.01 db

hence the decibel reading comes out to be 113.01 db


4 0
3 years ago
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