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olga2289 [7]
3 years ago
15

The titration of 10.00 mL of an HCl solution of unknown concentration requires 120.54 mL of a 0.100 M NaOH solution to reach the

equivalence point. What is the concentration of the unknown HCl solution?
Chemistry
1 answer:
kiruha [24]3 years ago
6 0

Answer:

Concentration of HCl is 1.2054 M

Explanation:

Acid-base titration is a type of qualitative analysis in which the concentration of the unknown acid/base is determined by treating it with a known concentration of base/acid. Indicators are used to determine the end point or the equivalence point (when all the acid/base is neutralized by base/acid).

At the end point,

Moles of acid = Moles of base

Since,

Molarity of a solution is given by the moles of solute per liter of the solution  

i.e.,

Molarity = moles of solute / volume of solution (in L)

moles = Molarity * Volume

moles = M * V  

M₁V₁ ( acid )= M₂V₂( base )

Where,

M₁ is the molarity of the acid

V₁ is the volume of the acid    

               

M₂ is the molarity of the base

V₂ is the total volume of the base

From the question,

M₁ =  ?

M₂ = 0.100 M

V₁ = 10.00 mL

V₂ = 120.54 mL

Using the above mentioned formula

M₁V₁ ( acid )= M₂V₂( base )

M₁ * 10.00mL = 0.100 M * 120.54 mL

M₁ = 1.2054 M

Hence, the concentration of of HCl is 1.2054 M

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What is the molar mass of (NH4)3 PO4? 113g, 121g, 149g, 339g
allochka39001 [22]
(NH4)3PO4 :

N = 14 * 3 =  42
H = 1 * 12 = 12
P = 31 * 1 = 31
O = 16 * 4 = 64
-------------------------
42+12+31+64 =  149 g / mol

Hope this helps!.


7 0
3 years ago
Determine the total time that must elapse until only ¼ of an original sample of the radioisotope Rn-222 remains unchanged.
Arte-miy333 [17]

Answer:

7.6 days

Explanation:

Radon is a radioactive element and Radon-222 is it's most stable isotope. The half-life of Radon-222 has been found to be approximately 3.8 days.

Let, the initial amount of the Rn-222 = 1 = A

Final amount = \frac{1}{4} = A'

We will use the following relation for calculating time elapsed in the decay

A' = A(\frac{1}{2} )^\frac{t}{t_1_/_2}  }

Thus,

\frac{1}{4} =1(\frac{1}{2} )^\frac{t}{3.8}

We can write is as,

(\frac{1}{2} )^2=(\frac{1}{2} )^\frac{t}{3.8}

Since the base in both sides are equal, powers can also be equal and thus,

2=\frac{t}{3.8}

So, t = 7.6 days

5 0
3 years ago
What mass of oxygen would form from 2.30 moles of water?
Serggg [28]

Answer : The mass of oxygen will be, 36.8 grams

Solution : Given,

Moles of water = 2.30 moles

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of oxygen.

The balanced chemical reaction will be,

2H_2O\rightarrow 2H_2+O_2

From the balanced reaction we conclude that

2 moles of water decomposes to give 1 mole of O_2

2.30 moles of water decomposes to give \frac{2.3}{2}=1.15 moles of O_2

Now we have to calculate the mass of oxygen.

\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2

\text{Mass of }O_2=(1.15moles)\times (32g/mole)=36.8g

Therefore, the mass of oxygen will be, 36.8 grams

8 0
3 years ago
Suppose you begin with 1.50~g of the hydrate copper(II)sulfate · x-hydrate (CuSO4· x H2O), where x is an integer. After dehydrat
chubhunter [2.5K]

These are two questions and two answers.

Question 1.

Answer: x = 5

Explanation:

1) Data:

m₁ = 1.50 g

compound₁: CuSO₄· x H₂O

m₂ = 0.96g

compound₂ = CuSO₄

x = ? (round to the nearest integer)

2) Solution:

i) molar mass of CuSO₄ = 63.546g/mol + 32.065g/mol + 4×15.999g/mol = 159.607g/mol

ii) number of moles of CuSO₄

number of moles = mass in grams / molar mass = 1.50 g/ 159.607 g/mol = 0.006265 mol

iii) molar mass of H₂O = 18.015 g/mol

iv) mass of H₂O = 1.50g - 0.96g = 0.54g

v) number of moles of H₂O = mass in grams / molar mass = 0.54 g / 18.015 g/mol = 0.0300 mol

vi) Ratio moles H₂O / moles CuSO₄ = 0.0300 / 0.0062625 ≈ 5

∴ x = 5.

Question 2.

Answer: 5.5 g

1) Data:

compound₁ = KAl(SO₄)₂ · 12H₂O.

compound₂ = KAl(SO₄)₂

m₂ = 3.0 g KAl(SO₄)₂

m₁ = ? (two significant figures)

2) Solution:

i) molar mass of KAl(SO₄)₂ = 39.098g/mol + 26.982g/mol + 2×32.065g/mol + 8×15.999g/mol = 258.202

ii) number of moles of KAl(SO₄)₂ = mass in grams / molar mass = 3.0g / 258.202 = 0.011619 mol

iii) number of moles of H₂O = 12 × number of moles of KAl(SO₄)₂ = 12 × 0.011619*12 mol = 0.1394 moles

iv) mass of H₂O = number of moles × molar mass = 0.1394 moles × 18.015 g/mol = 2.5 g (rounded to two significant figures)

v) mass of the original compound = mass of KAl(SO₄)₂ + mass of H₂O = 5.5g

6 0
3 years ago
A reaction that has two compounds as reactants and two compounds as products is most likely a
ryzh [129]

Answer:

synthesis reaction

Explanation:

A synthesis reaction occurs when two or more reactants combine to form a single product. In a decomposition reaction, one reactant breaks down into two or more products. This is the reverse of a synthesis reaction. Replacement reactions occur when elements switch places in compounds.

7 0
3 years ago
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