Answer:
(0,-8)
x=0
y=-8
Step-by-step explanation:
There are a couple of ways you can solve this I used what I think is called the elimination method
We first start by writing the equations in linear form (y=mx+b)
For the first one we have -12x-5y=40
we add 5y to both sides and subtract 40 to get
-12x-40=5y
divide by 5 to get
-12/5x-8=y
Then the second one we have
12x-11y=88
same deal here, add 11y and subtract 88 to get
12x-88=11y
divide by 11 and get
12/11x-8=y
We then set the two equations equal to each other and get
-12/5x-8=12/11x-8
We can add 8 to both sides and get
-12/5x=12/11x
Just by looking at it you can see that the only solution for x is 0
Plug in 0 to the first equation and get -12*0-5y=40
This means that -5y=40
Solve for y and get -8
Cotangent is one over tangent
1/(4/7)
Answer 7/4
Answer: x-intercept :12 & y-intercept ;-8
Step-by-step explanation:To find the x-intercept ,substitute in 0 for y and solve for x .
8x-12y=96
8x-12(0)=96
8x=96 (divide both # by 8)
x=12
To find the y-intercept ,substitute in 0 for x and solve for y .
8(0)-12y=96
-12y=96(Divide by -12 both )
y=-8
36*41.5=1494
1494 is the area
<A +<B + < C =180° ==>(5x+6) + (2x+1) + (6x+4) = 180°
13x = 180°-11° ==> 13x 169° and x =169/13 =13°
