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3 years ago

Triangle ABC is transformed to triangle A′B′C′, as shown below:

Mathematics

1 answer:

Montano1993 [528]3 years ago

3 0

Answer:

C. m<CAB = m<C'A'B'

Step-by-step explanation:

Triangle ABC looks like it was only reflected over the line y = 0. If the triangle was only reflected then the triangles should be congruent to each other.

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Solve x2 − 8x + 5 = 0 using the completing-the-square method. (2 points)

RoseWind [281]

Answer:

$x = 4 + \sqrt{11}, \: \: x = 4 - \sqrt{11}$

Step-by-step explanation:

${x}^{2} -8x + 5 = 0 \\ \\ {x}^{2} - 8x + {4}^{2} = - 5 + {4}^{2} \\ \\ {(x - 4)}^{2} = - 5 + 16 \\ \\ {(x - 4)}^{2} = 11 \\ \\ x - 4 = \pm \sqrt{11} \\ \\ x = 4 \pm \sqrt{11} \\ \\ x = 4 + \sqrt{11}, \: \: x = 4 - \sqrt{11}$

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3 years ago

Plz solve fast!<br> what is the answer of this quation.

Alex_Xolod [135]

49 is the answer to ur question

3 0

3 years ago

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rusak2 [61]

Answer:

the answer to the problem is -18

8 0

3 years ago

Show how to make ten to solve 13-7. Write in a number sentence. _-_-_-_-_=_

ser-zykov [4K]

Answer: The answer is 6.

The number sentence is

3-3=0

10-4=6

So, 13-7=6

Step-by-step explanation:

To solve $13-7$ , by making ten

First break 13 and write $13=10+3$

Then break 7 as $7=3+4$

Now to subtract 7 from 13,

Step 1. Subtract 3 (a part of 7), from 3(a part of 13) or cross 3 circles, then we have left 10-4

$13-7=10+3-(3+4)=10+3-3-4=10-4$

Step 2. Subtract 4 from 10 or cross 4 circles out of 10, we get 6.

The answer is 6.

5 0

3 years ago

Read 2 more answers

Log (3x+1) - Log (2x+5)= 1

sleet_krkn [62]

Answer:

$\huge \red { \boxed{x = - \frac{49}{17}}}$

Step-by-step explanation:

$log(3x + 1) - log(2x + 5) = 1 \\ \\ log \: \frac{3x + 1}{2x + 5} = log \: 10..( \because \: log \: 10 = 1) \\ \\ \frac{3x + 1}{2x + 5} = 10 \\ \\ 3x + 1 = 20x + 50 \\ 3x - 20x = 50 - 1 \\ \\ - 17x = 49 \\ \\ x = \frac{49}{ - 17} \\ \\ \huge \purple{ \boxed{x = - \frac{49}{17}}} \\$

6 0

3 years ago