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3 years ago

14 in USE 3.14 for pi

Mathematics

1 answer:

Gnesinka [82]3 years ago

3 0

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a baker has 6 small bags of flour.Eaxh bag weighs 1 pound . she divides each bag into thirds . How many 1/3 pound bags of flour

Naddika [18.5K]

If she had 6 bags before and each bag became three, the total number is 6*3=18 bags.

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4 years ago

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A machine makes errors in a certain operation with probability p. There are two types of errors. The fraction of errors that are

Crank

Answer:

Step-by-step explanation:

The concept of binomial probability is applied.

Mathematically from binomial probability ; (nCx)px(1−p)(n-x)

The detailed step by step is as shown in the attachment

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3 years ago

Casey is completing an experiment that requires 300 mL of potassium chloride (KCl) at a concentration of 0.2 M. But Casey's lab

gulaghasi [49]

What you first need to do is make an equation. Then plug that equation into photomath and you get your answer

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3 years ago

What is the area of the shaded portion of the circle?

SOVA2 [1]

Answer:

The first option is the correct one, the area of the shaded portion of the circle is

[/tex](5 \pi -11.6)ft^2[/tex]

Step-by-step explanation:

Let us first consider the triangle + the shadow.

The full area of the circle is the radius squared times pi, so

A= $(5 ft)^2 \cdot \pi \\25 ft^2 \cdot \pi$

Since $\frac{72^{\circ}}{360^{\circ}}=\frac{1}{5}$ , the area of the triangle + the shaded area is one fifth of the area of the whole circle, thus

$A_1=\frac{1}{5}25 ft^2 \cdot \pi\\ =5 ft^2 \cdot \pi$

If we want to know the area of the shaded part of the circle, we must subtract the area of the triangle from $A_1$ .

The area of the triangle is given by

$A_{triangle}=\frac{1}{2}\cdot (2.9+2.9)ft \cdot 4 ft\\= 11.6 ft^2$

Thus the area of the shaded portion of the circle is

$A_1-A_{triangle}=5 \pi ft^2-11.6ft^2\\= (5 \pi -11.6)ft^2$

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3 years ago

Solve the equation x + 3 x + 5 equal 21

saw5 [17]

Answer:

x = 4

Step-by-step explanation:

Combining like terms, we get 4x = 16, and so x = 4.

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4 years ago

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