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3 years ago

15

14 in USE 3.14 for pi

1 answer:

Gnesinka [82]3 years ago

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-8 + 5x - 2 = 20 solve

vaieri [72.5K]

Combining like terms on the left-hand side gives us $5x-10=20.$ Adding 10 to both sides gives $5x=30,$ and dividing both sides by 5 gives our answer of $\boxed{x=6}.$

3 0

3 years ago

Let g(x) = – x^2 + 4x + 3. Find and simplify g(-3).

Evgen [1.6K]

Steps to solve:

g(x) = – x^2 + 4x + 3 when g(-3).

~Substitute x with -3.

g(-3) = -(-3)^2 + 4(-3) + 3

~Simplify

g(-3) = -9 - 12 + 3

~Simplify using PEMDAS

g(-3) = -18

Best of Luck!

7 0

3 years ago

Read 2 more answers

Find the area of the composite figure.

Minchanka [31]

Answer:

132 square feet

Step-by-step explanation:

The formula for the area of a triangle is 1/2 * b * h. B stands for base and h stands for height. 1/2 multiplied by the base, 10, is 5. We then multiply 5 by 12 which is 60. Let's look at the rectangle now. The area of a rectangle is length by width. The length is 12ft and the width is 6ft. 12 * 6 = 72. 72+60=132 square feet.

8 0

2 years ago

Of all customers purchasing automatic garage-door openers, 75% purchase Swedish model. Let X = the number among the next 15 purc

Lelechka [254]

Answer:

a)

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

b)

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = 0.2737

d) μ = 15*0.75 = 11.25. σ² = 11.25*0.25 = 2.8125

Step-by-step explanation:

X is a binomial random variable with parameters n = 15, p = 0.75. Therefore

a)

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

b)

P(X>10) = P(X=11) + P(X=12)+ P(X=13)+P(X=14)+P(x=15)

$P(X=11) = {15 \choose 11} * 0.75^{11} * 0.25^4 = 0.2252$

$P(X=12) = {15 \choose 12} * 0.75^{12} * 0.25^3 = 0.2252$

$P(X=13) = {15 \choose 13} * 0.75^{13} * 0.25^2 = 0.1559$

$P(X=14) = {15 \choose 14} * 0.75^{14} * 0.25 = 0.0668$

$P(X=15) = {15 \choose 15} * 0.75^{15} = 0.0134$

Thus,

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = P(X = 6) + P(X = 7) + P(X = 8) + P(X=9) + P(X=10)

$P(X=6) = {15 \choose 6} * 0.75^{6} * 0.25^9 = 0.0034$

$P(X=7) = {15 \choose 7} * 0.75^{7} * 0.25^8 = 0.0131$

$P(X=8) = {15 \choose 8} * 0.75^{8} * 0.25^7 = 0.0393$

$P(X=9) = {15 \choose 9} * 0.75^{9} * 0.25^6 = 0.0918$

$P(X=10) = {15 \choose 10} * 0.75^{10} * 0.25^{5} = 0.1652$

Thereofre,

$P(6 \leq X \leq 10) = 0.0034 + 0.0134 + 0.0393 + 0.0918 + 0.1652 = 0.2737$

d) μ = n*p = 15*0.75 = 11.25

σ² = np(1-p) = 11.25*0.25 = 2.8125

3 0

3 years ago

Evaluate the following intervals<br>x^-4dx

igor_vitrenko [27]

Answer:

simplified:

$\frac{d}{x^3}$

and Find the integral if that's what you also wanted:

$-\frac{1}{3x^3} +3$

8 0

2 years ago