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3 years ago

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How many moles of oxygen are required to produce 4.62 moles of carbon monoxide that is formed by direct combination of its eleme

nts?

1 answer:

mariarad [96]3 years ago

5 0

Answer: 6.01

Explanation:

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Water is flowing in a pipe with a mass flow rate of 100.0 lb/h (M water H,O=18.016). What is the (i) Molar flow rate of H20 (gmo

Arada [10]

Answer:

i) 0,7 molH20/s

ii)11,2 g O/s

iii)1,4 g H/s

Explanation:

i) To find the molar flow rate of water, we just convert the mass of water to moles of water using its molecular weight(g/mol) and changing to the proper units (lb to grames and hours to seconds):

$100 \frac{lb}{h}*\frac{453,5g}{1 lb}*\frac{1molH20}{18,016g}*\frac{1h}{3600s}=0,7\frac{molH20}{s}$

ii) Now we just consider the oxygen in the water stream (for 1 mole of water there is 1 mole of oxygen):

$100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{1molO}{1molH20}*\frac{16gr}{1molO}*\frac{1h}{3600s}=11,2\frac{gO}{s}$

iii)Just considering the hydrogen in the stream (for 1 mole of water there is 2 moles of hydrogen):

$100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{2molH}{1molH20}*\frac{1gr}{1molH}*\frac{1h}{3600s}=1,4\frac{gH}{s}$

3 0

2 years ago

Complete and balance the molecular equation for the reaction of aqueous sodium sulfate, Na2SO4, and aqueous barium nitrate, Ba(N

Rina8888 [55]

Answer:

1. The balanced molecular equation is given below:

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + 2NaNO3(aq)

2. The net ionic equation is given below:

SO4^2-(aq) + Ba^2+(aq) —> BaSO4(s)

Explanation:

1. The balanced molecular equation

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + NaNO3(aq)

The above equation can be balance as follow:

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + NaNO3(aq)

There are 2 atoms of Na on the left side and 1 atom on the right side. It can be balance by putting 2 in front of NaNO3 as shown below:

Na2SO4(aq) + Ba(NO3)2(aq) —> BaSO4(s) + 2NaNO3(aq)

Now, the equation is balanced.

2. The bal net ionic equation.

This can be obtained as follow:

Na2SO4(aq) + Ba(NO3)2(aq) —>

In solution, Na2SO4 and Ba(NO3)2 will dissociate as follow:

Na2SO4(aq) —> 2Na^+(aq) + SO4^2-(aq)

Ba(NO3)2(aq) —> Ba^2+(aq) + 2NO3^-(aq)

Na2SO4(aq) + Ba(NO3)2(aq) —>

2Na^+(aq) + SO4^2-(aq) + Ba^2+(aq) + 2NO3^-(aq) —> BaSO4(s) + 2Na^+(aq) + 2NO3^-(aq)

Cancel the spectator ions i.e Na^+ and NO3^- to obtain the net ionic equation.

SO4^2-(aq) + Ba^2+(aq) —> BaSO4(s)

7 0

3 years ago

____ 26. what is the weight percentage of nitrogen in urea, cn2h4o

Paraphin [41]

Weight percentage of nitrogen can be calculated using the following rule:
weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100

From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of hydrogen = 1 grams
molecular mass of oxygen = 16 grams

therefore:
mass of nitrogen in urea = 2(14) = 28 grams
mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams

Substitute with the masses in the equation to get the percentage:
weight percentage of nitrogen = (28/60) x 100 = 46.667%

7 0

3 years ago

"Synthesis gas" is a mixture of carbon monoxide and water vapor. At high temperature synthesis gas will form carbon dioxide and

Pavlova-9 [17]

Answer:

Check the explanation

Explanation:

Lets start by drawing the ICE chart

reaction is

...............CO + H2O ========= CO2 + H2

I.............2.6.........3.4..........................0................0

E...........1.88........2.68......................0.72............0.72

since reaction is 1 : 1 if 0.72 atm of H2 are produced then the same amount of CO2 will be formed

calculate Kp this is the relationship between the pressure of products and the pressure of reactants

Kp = Pproducts / Preactants = [Pco2* PH2] / [PCO * PH2O]

Kp = 0.72 * 0.72 / (1.88 * 2.68) = 0.1029

Write the ICE chart again

...............CO + H2O ========= CO2 + H2

I.............1.88.........2.68+1.1.................0.72................0.72

C...........-x............. -x..............................+x........................+x

E......1.88 - x...........3.78-x.....................0.72+x..... ..0.72+x

Kp is = (0.72+x)*(0.72+x) /[ (1.88-x)*(3.78-x) ] = 0.1029

lets say that x is the change of pressure.

If you solve this equation you will get a value of x equal to 0.1

Pressure of CO2 is

0.72 + 0.1= 0.82 atm

using 2 sig figures this would be

8.2x10-1 atm

6 0

3 years ago

Read 2 more answers

Convert 150 g/L to the unit g/mL.

inn [45]

The correct answer is C 0.15 g/mL.

4 0

3 years ago