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zalisa [80]
3 years ago
12

How many moles of oxygen are required to produce 4.62 moles of carbon monoxide that is formed by direct combination of its eleme

nts?
Chemistry
1 answer:
mariarad [96]3 years ago
5 0

Answer: 6.01

Explanation:

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Name a machine used to reap, thresh and clean the crop.<br>i will give brainliest who answers first
meriva

Answer:

combine harvester, or a combiner.

4 0
2 years ago
The atomic radius of main group elements generally increases down a group because
Pachacha [2.7K]

The atomic radius of main group elements generally increases down a group because as there are more electrons they are farther away from the nucleus and the electrons closer to the nucleus shield the outer electrons from the protons for attraction.

8 0
3 years ago
File:
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8 0
3 years ago
What population would be hurt if the bear population was to increase
KengaRu [80]
Fish would be hurt because that’s what bears mostly eat
7 0
3 years ago
The pyrolysis of ethane proceeds with an activation energy of about 300 kJ/mol. How much faster is the decomposition at 625°C th
Alona [7]

Answer:

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_2 = rate of reaction at T_2

K_1 = rate of reaction at T_1

Ea = activation energy of the reaction

R = gas constant = 8.314 J/K mol

E_a=300 kJ/mol=300,000 J/mol

T_2=625^oC=898.15 K,T_1=525^oC=798.15 K

\log (\frac{K_2}{K_1})=\frac{300,000 J/mol}{2.303\times 8.314 J/K mol}[\frac{1}{798.15 K}-\frac{1}{898.15 K}]

\log (\frac{K_2}{K_1})=2.185666

K_2=153.344\times K_1

The decomposition of ethane is 153.344 times much faster at 625°C than at 525°C.

4 0
3 years ago
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