Potassium Chloride = KCl
KCl has a molar mass of: 39.0983g+35.4530g=74.5513g
The number of moles of KCL we are adding is:
2g/(74.5513g/mol) = 0.02683 mol
But you have to keep in mind that salts in
water dissociate:
KCl -> K+ + Cl-
So 1 mole KCl is 2 osmoles (because it’s
two particles)
So if you add 0.02683 moles, you are adding
0.02683*2 = 0.05366 osmoles.
If you dissolve them in 1 liter, you have a solution 0.05366 OsM = 53.66 mOsM
D5W = dextrose 260 mOsM
1/2 Normal Saline =
has half of the normal saline concentration - a normal saline solution has the
same sodium chloride concentration as blood serum = 154 mOsm
You have to sum up all the osmolarities:
<span>= </span>53.66 mOsM + 154 mOsM + 260 mOsM = 467.66 mOsM
Convert all the grams to moles first.
K - 3.65 g / 39.1 g/mol = 0.0934 mol
Cl - 3.33 g / 35.45 g/mol = 0.0939 mol
O - 3.02 g / 16 g/mol = 0.189 mol
Divide them all by the smallest number of moles (0.0934 moles of K) to get whole numbers.
K - 0.0934/0.0934 = 1
Cl - 0.0939/0.0934 ≈ 1
O - 0.189/0.0934 ≈ 2
KClO2
The original results have not been replicated consistently and reliably.
I believe the correct response would be A. Energy being absorbed, as temperature increase must for instance occur for the reaction to occur, this increase in temperature for the reacting substances indicates energy being absorbed as the reaction proceeds.
