What element marks the boundary between using fusion and fission to release energy?

Identify the cfc with the shortest atmospheric lifetime

goldenfox [79]

CFC-11 is typically the CFC with the shortest atmospheric lifetime.

5 0

3 years ago

When mud and water are combined the result is a

gulaghasi [49]

Answer:

More wetter mud

I hope this was helpful

8 0

3 years ago

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How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl2 completely react given the reaction: BaCl2 (aq) + Na2

jeyben [28]

<u>Answer:</u> The amount of barium sulfate produced in the given reaction is 0.667 grams.

<u>Explanation:</u>

To calculate the number of moles from molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of barium chloride = 0.113 M

Volume of barium chloride = 25.34 mL = 0.02534 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.113mol/L=\frac{\text{Moles of barium chloride}}{0.02534L}\\\\\text{Moles of barium chloride}=0.00286mol$

For the given chemical reaction:

$BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow BaSO_4(s)+2NaCl(aq.)$

By Stoichiometry of the reaction:

1 mole of barium chloride is producing 1 mole of barium sulfate.

So, 0.00286 moles of barium chloride will produce = $\frac{1}{1}\times 0.00286mol=0.00286mol$ of barium sulfate.

Now, to calculate the mass of barium sulfate, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of barium sulfate = 233.38 g/mol

Moles of barium sulfate = 0.00286 moles

Putting values in above equation, we get:

$0.00286mol=\frac{\text{Mass of barium sulfate}}{233.38g/mol}\\\\\text{Mass of barium sulfate}=0.667g$

Hence, the amount of barium sulfate produced in the given reaction is 0.667 grams

4 0

4 years ago

Hydrogen sulfide decomposes according to the following reaction, for which Kc = 9.30 10-8 at 700°C. 2 H2S(g) 2 H2(g) + S2(g) If

Vikentia [17]

Answer:

The equilibrium concentration of hydrogen gas is 0.0010 M.

Explanation:

The equilibrium constant of the reaction = $K_c=9.30\times 10^{-8$ }

Moles of hydrogen sulfide = 0.31 mol

Volume of the container = 4.1 L

$[concentration]=\frac{moles}{volume (L)}$

$[H_2S]=\frac{0.31 mol}{4.1 L}=0.076 M$

$2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)$

Initially

0.076 M

At equilibrium

(0.076-2x) 2x x

The expression of an equilibrium constant :

$K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}$

$9.30\times 10^{-8}=\frac{(2x)^2\times x}{(0.076-x)^2}$

Solving for x:

x = 0.00051

The equilibrium concentration of hydrogen gas:

$[H_2]=2x=2\times 0.00051 M=0.0010 M$

4 0

4 years ago

Is baking cake a acid base reaction

Zinaida [17]

When baking powder is added to a cake, the acid base reaction it undergoes with the acidic butter produces the carbon dioxide that makes the cake rise.

6 0

3 years ago