A scuba diver knows that she needs 50.0mol of air for an upcoming dive. What size (volume) tank will she need to fill for this d
1 answer:
Answer:
1120 L.
Explanation:
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In this case, as no conditions of pressure of temperature are given for this problem, we can assume that the scuba diver dives at STP (1 atm and 273.15 K), which means that 1 mole of air would occupy a volume of 22.4 L.
In such a way, since she needs 50.0 moles of air, the following ratio is useful to compute the size (volume) of the tank she needs:
Thereby, we plug in to obtain:
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Answer : The mass of occupy 30.3 L under the same conditions will be, 24.9 grams.
Explanation :
First we have to calculate the moles of
Now we have to calculate the moles of in 30.3 L by using Avogadro's law.
Avogadro's law : It is defined as the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.
or,
where,
= initial volume of gas = 6.21 L
= final volume of gas = 30.3 L
= initial moles of gas = 0.16 mol
= final temperature of gas = ?
Now put all the given values in the above equation, we get:
Now we have to calculate the mass of
Molar mass of = 32 g/mol
Therefore, the mass of occupy 30.3 L under the same conditions will be, 24.9 grams.