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Nataly [62]
3 years ago
12

How wold you identify an arrhenius acid in a chemical equation

Chemistry
2 answers:
Lady_Fox [76]3 years ago
8 0

An Arrhenius acid is a compound that increases the H + ion concentration in aqueous solution. The H + ion is just a bare proton, and it is rather clear that bare protons are not floating around in an aqueous solution.
cupoosta [38]3 years ago
6 0

Answer:

Explanation:

An Arrhenius acid is any species that increases the concentration of H+start text, H, end text, start superscript, plus, end superscript in aqueous solution. An Arrhenius base is any species that increases the concentration of OH−start text, O, H, end text, start superscript, minus, end superscript in aqueous solution.

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An ionic solid is placed in water. which information is described by the solubility product constant?
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Answer:

\boxed{\text{C. the equilibrium between the solid and its ions in solution}}

Explanation:

\rm MX(s) $\, \rightleftharpoons \,$ M$^{+}$(aq) + $^{-}$(aq); $K_{\text{sp}}$ = [M$^{+}$][X$^{-}$]\\\\\text{$K_{\text{sp}}$ gives us information on}\\\\\boxed{\textbf{ the equilibrium between the solid and its ions in solution}}

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(06.04 HC)
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The mass of sodium chloride at the two parts are mathematically given as

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  • mass of Nacl(m)=39.15g

<h3>What is the mass of sodium chloride that can react with the same volume of fluorine gas at STP?</h3>

Generally, the equation for ideal gas is mathematically given as

PV=nRT

Where the chemical equation is

F2 + 2NaCl → Cl2 + 2NaF

Therefore

1.50x15=m/M *(1.50*0.0821)

1-50 x 15=m/58.5 *(1.50*0.0821)

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Part 2

PV=m'/MRT

1*15=m'/58.5*0.0821*273

m'=39.15g

mass of Nacl(m)=m'=39.15g

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