<span>Segment EG is half the length of segment BH because of the Midsegment theorem</span>
4x/15 = 60/x
4x^2 = 900
x^2 = 225
x = 15
Answer:
0.163
Step-by-step explanation:
P = I (1 + r)ᵗ
450 = 56 (1 + r)⁶
8.036 = (1 + r)⁶
log₆ 8.036 = 1 + r
log 8.036 / log 6 = 1 + r
1.163 = 1 + r
r = 0.163
Answer:
1,166 frascos
Step-by-step explanation:
4500 -2456=2044
2044 - 1678=366
366 + 800= 1166
The square of the diagonal (d1) of the end face is
.. (d1)^2 = (3 in)^2 +(5 in)^2 = (9 +25) in^2 = 34 in^2
The square of the longest diagonal (d2) will be given by
.. (d2)^2 = (3x in)^2 +(d1)^2
.. = (9x^2 +34) in^2
So, the longest diagonal is
.. d2 = √(9x^2 +34) in
