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dimaraw [331]
3 years ago
13

Write the equation of the line that is perpendicular to y = 2x - 4 that goes through

Mathematics
2 answers:
user100 [1]3 years ago
5 0

Answer:

y = 2x + 13

Step-by-step explanation:

tigry1 [53]3 years ago
3 0
Y = 2x +13

hold this helps!
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The square root of 198 is between which two numbers?
Schach [20]

Answer:

<u>The square root of 198 is between 14 and 15.</u>

Step-by-step explanation:

Let's calculate the square root of 198, this way:

√198 = 14.07

<u>The square root of 198 is between 14 and 15.</u>

4 0
3 years ago
Riddle what 3D shape should be afraid of?
Digiron [165]
Well a sphere ok ok :)
4 0
3 years ago
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What is y+4=9 what is y?
amid [387]

Answer:

y = 5

Step-by-step explanation:

Subtract the 4 from 9

5 0
4 years ago
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F(x)=3x-7 find the value of c so that f(c) =20 is true
Andreas93 [3]

<u>Answer</u>:

c = 9

<u>Explanation</u>:

given: f(x)=3x-7

<em>if f(c) =20</em>

To solve this replace x with c and then y is 20.

<u>Solve</u>:

3c - 7 = 20

3c = 27

c = 27 ÷ 3

c = 9

7 0
2 years ago
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Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
juin [17]

Answer:

The Taylor series of f(x) around the point a, can be written as:

f(x) = f(a) + \frac{df}{dx}(a)*(x -a) + (1/2!)\frac{d^2f}{dx^2}(a)*(x - a)^2 + .....

Here we have:

f(x) = 4*cos(x)

a = 7*pi

then, let's calculate each part:

f(a) = 4*cos(7*pi) = -4

df/dx = -4*sin(x)

(df/dx)(a) = -4*sin(7*pi) = 0

(d^2f)/(dx^2) = -4*cos(x)

(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4

Here we already can see two things:

the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.

so we only will work with the even powers of the series:

f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....

So we can write it as:

f(x) = ∑fₙ

Such that the n-th term can written as:

fn = (-1)^{2n + 1}*4*(x - 7*pi)^{2n}

6 0
3 years ago
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