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zvonat [6]
2 years ago
11

The length and breadth of a rectangular field are 312m and 186m respectively; correct to the nearest metres. Between what limits

must the field's perimetre lie? (Write your final answer as an inequality)​
Mathematics
1 answer:
lisabon 2012 [21]2 years ago
8 0

Answer:

P \geq 1000 \; meters

Step-by-step explanation:

<u>Given the following data;</u>

Length = 312 meters

Breadth = 186 meters

To find the perimeter of the rectangle;

Mathematically, the perimeter of a rectangle is given by the formula;

Perimeter = 2(L + W)

Perimeter = 2(312 + 186)

Perimeter = 2(498)

Perimeter = 996 meters

To the nearest meters, we have;

Perimeter = 996 ≈ 1000 meters

Let P represent the perimeter of a rectangular field.

900 < P > 1000

Therefore, P \geq 1000 \; meters

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the sum of two numbers is 63. one ninth of the first number plus one sixth of the second number is 21. find the numbers
PSYCHO15rus [73]

Answer: x= -189, y =252

Step-by-step explanation:

Let the first number be x and second number be y

so

x + y = 63

x = 63-y

now

1/9 of x + 1/6 of y = 21

x/9 + y/6 = 21

substituting x's value from equation i

(63-y)/9 + y/6 = 21

(378-6y+9y)/54 = 21

378+3y = 1134

3y = 1134-378

so, 3y = 756

so, y = 756/3

so, y = 252

now

x = 63-252

so, x = -189

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3 years ago
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iVinArrow [24]
 3x+7 = 51-x
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x = 11

answer
x = 11
4 0
3 years ago
What is the perimeter of a Polygon with vertices at (3,2),(3,9),(7,12),(11,9), and (11,2)?
jeka57 [31]

Answer:

The perimeter is 32.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the eighth term of the arithmetic sequence? An=<br> 10n – 14?
Alja [10]

Answer:

A8 = 66 [8th term]

Step-by-step explanation:

Given the explicit arithmetic sequence An = -14 + 10n → -4 + 10(n-1)

To find the 8th term. An nth term is where n is n in the sequence. So substitute 8 for n, and simplify.

So A8 = -4 + 10(8-1) → -4 + 10(7) → -4 + 70 → 70 - 4 → 66.

3 0
3 years ago
Please answer question three and four if you can :)<br> Show full working out ty;)
nikklg [1K]

Step-by-step explanation:

3

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

D = ( \frac{2 + 5}{2},  \:  \:  \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \:  \:  \frac{ 1}{2} ) \\ \therefore D= (3.5, \:  \: 0.5) \\  \& \: A=(-1,\:\:4)...(given) \\\\  now \: by \: distance \: formula \\  \\ Length  \: of \:  segment  \: AD \\  =  \sqrt{( - 1 - 3.5)^{2}  +  {(4 - 0.5)}^{2} }  \\ =  \sqrt{(4.5)^{2}  +  {(3.5)}^{2} }  \\ =  \sqrt{20.25 + 12.25 }  \\  =  \sqrt{32.5}  \\    \red{ \boxed{\therefore Length  \: of \:  segment  \: AD  = 5.7 \: units}}

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

4 0
3 years ago
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