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kirill [66]
3 years ago
8

How do I do this or whats the answer im so lost and having a mental breakdown ✌​

Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

you'll have to multiply 8 by itself to get your area so you have to do 8*8

Step-by-step explanation:

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Read 2 more answers
SOLVE USING THE QUADRATIC FORMULA <br><br> 1) y=3x^2-x-6<br><br> 2) y=-5x^2+7x+3
kondor19780726 [428]

1) x=\frac{1+\sqrt{73}}{6}\,\,and\,\,x=\frac{1-\sqrt{73}}{6}

2) x=\frac{-7+\sqrt{109}}{-10}\,\,and\,\,x=\frac{-7-\sqrt{109}}{-10}

Step-by-step explanation:

Solving the equations using quadratic formula.

1) y=3x^2-x-6

The quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

where a =3, b = -1 and c= -6

Putting values:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-1)\pm\sqrt{(-1)^2-4(3)(-6)}}{2(3)}\\x=\frac{1\pm\sqrt{1+72}}{6}\\x=\frac{1\pm\sqrt{73}}{6}\\so, x=\frac{1+\sqrt{73}}{6}\,\,and\,\,x=\frac{1-\sqrt{73}}{6}

2) y=-5x^2+7x+3

The quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

where a =-5, b = 7 and c= 3

Putting values:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(7)\pm\sqrt{(7)^2-4(-5)(3)}}{2(-5)}\\x=\frac{-7\pm\sqrt{49+60}}{-10}\\x=\frac{-7\pm\sqrt{109}}{-10}\\So, x=\frac{-7+\sqrt{109}}{-10}\,\,and\,\,x=\frac{-7-\sqrt{109}}{-10}

Keywords: Solving Using Quadratic Formula

Learn more about Solving Using Quadratic Formula at:

  • brainly.com/question/10666510
  • brainly.com/question/4460262
  • brainly.com/question/7361044

#learnwithBrainly

3 0
4 years ago
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