Answer:
Left amount of Polonium-210 after 115 days will be 4.5927 microgram
Explanation:
We have given initial mass of Polonium-210 
Decay rate x= 0.502% = 0.00502
Time t = 115 days
We have to find the left amount of Polonium -210 after 115 days
We know that left amount is given by
So left amount of Polonium-210 after 115 days will be 4.5927 microgram
Answer:
If the lac enzyme continues to be produced even in the absence of lactose, the cell will be expending energy unnecessarily and this will be a problem for the supply of energy for other metabolic processes.
If the lac operator gene is dragged to any stretch of DNA, that gene may provide an inadequate reading generating a mutation.
Explanation:
The lac operon is an essential molecule for the transport and metabolism of lactose in microorganisms. This molecule has a fundamental function in the life of these single-celled organisms and must be synthesized immediately when lactose is present in the organism, however, its synthesis must be stopped as soon as the lactose is metabolized, otherwise the cell can spend energy unnecessarily preventing others Metabolic processes take place, which is a big problem if you only have one cell.
In addition, if for some reason, the lac operon gene is dragged on the DNA strand, an incorrect reading of the DNA bases can occur, which can cause mutations.
Answer:
I would say overpopulation
Thus because when they are trying to navigate through jungles, they are destorying whats in their path, without realizing. There are so many of the elephants it just keeps happening over and over like a cycle.
Assumptions:
1. Equilibrium has been reached for the allele proportions
2. Absence of <span>evolutionary influences such as </span>mate choice<span>, </span>mutation<span>, </span>selection<span>, </span>genetic drift<span>, </span>gene flow<span> and </span>meiotic drive<span>.
</span>
Defining L=long stem, l=short stem, and L is dominant over l.
f(x) = frequency of allele x (expressed as a fraction of population)
Then the Hardy-Weinberg equilibrium law applies:
p^2+2pq+q^2=1
where
f(LL)=p^2
f(Ll)=2pq
f(ll)=q^2
Given f(ll)=0.35=q^2, we have
q=sqrt(0.35)=0.591608
p=1-q=0.408392
=>
f(Ll)
=2pq
=2*0.408392*0.591608=0.483216
= proportion of heterozygous population
Answer: percentage of heterozygous population is 48.32%
