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Dmitry [639]
3 years ago
8

For what values of b, the equation x^2−ax+b=0 has a solution for any value of a? PLEASE I NEED IT SOON!

Mathematics
2 answers:
kondor19780726 [428]3 years ago
6 0

If you choose b=0 the equation becomes

x^2-ax = 0 \iff x(x-a) = 0

which always has solutions x=0,\ x=a


Rasek [7]3 years ago
3 0
I’m not sure about the wording of the question, but wouldn’t it be all real numbers?
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