Question

For what values of b, the equation x^2−ax+b=0 has a solution for any value of a? PLEASE I NEED IT SOON!

Answer 1

If you choose $b=0$ the equation becomes

$x^2-ax = 0 \iff x(x-a) = 0$

which always has solutions $x=0,\ x=a$

Answer 2

I’m not sure about the wording of the question, but wouldn’t it be all real numbers?