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3 years ago

For what values of b, the equation x^2−ax+b=0 has a solution for any value of a? PLEASE I NEED IT SOON!

Mathematics

2 answers:

kondor19780726 [428]3 years ago

6 0

If you choose $b=0$ the equation becomes

$x^2-ax = 0 \iff x(x-a) = 0$

which always has solutions $x=0,\ x=a$

Rasek [7]3 years ago

3 0

I’m not sure about the wording of the question, but wouldn’t it be all real numbers?

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Free_Kalibri [48]

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Step-by-step explanation:

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