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2 years ago

The quotient of dividing a number by 4 is 5. Find the number.

Mathematics

1 answer:

PtichkaEL [24]2 years ago

3 0

Answer: 20

Step-by-step explanation:

A quotient is th value that is gotten when two numbers are divided. Based on the information given in the question, let the number be represented by x.

Therefore, x/4 = 5

x = 4 × 5

x = 20

The number is 20

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a pitcher of fruit punch holds 2 gallons if 9 people share the entire pitcher equally how much punch does each person get

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Explanation: so, you divide. why do I know this? because it doesn't say "times," (multiplication word) "more than," (addition word) "less than/ left over." (subtraction word) so what your looking for is "equally," and "each."

So, can you do 2÷9? no, you cant. so you have to multiply 2×9 to get the answer. and what's the answer? 18!

so, now, can you divide 18÷9? yes!! why? because you can only divide big numbers like 18. and you can't divide small numbers like 2 or 9. do you get what I'm saying?

so, what's 18÷9? 2!!

I hope this helps! :) if you still don't understand it just please let me know :)

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2 years ago

A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a

Natali [406]

Answer:

(a)

The probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

$p^4 (1-p)$

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

$(1-p)^4p$

Therefore the probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

7 0

2 years ago

The quotient of dividing a number by 4 is 5. Find the number.​

The quotient of dividing a number by 4 is 5. Find the number.